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notsponge [240]
2 years ago
12

The moon remains in Earth's orbit because of Earth's gravitational pull on the moon. In return, the moon exerts a gravitational

pull on Earth. The mass of the moon is 0.07346 x 1024 kg and Earth's mass is 5.9724 x 1024 kg. How does the gravitational pull of Earth on the moon compare to the moon's gravitational pull on Earth?
A. Earth pulls more strongly on the moon.
B. The moon pulls more strongly on Earth.
C. The moon and Earth pull on each other with equal force.
D. There is not enough information to answer this question.
Physics
1 answer:
Vladimir [108]2 years ago
3 0

Given what we know, we can confirm that the Earth pulls more strongly on the moon, option A is correct.

<h3 /><h3>Why does the Earth pull more strongly?</h3>

This has to do with the relationship between the mass of an object and its gravitational pull. These values are <u>directly proportional</u>, the more massive an object is, the stronger the gravitational pull that object exhibits. The moon does pull on the Earth as well, however, due to its smaller mass, it does not pull as strongly as the Earth on the moon.

Therefore, we can confirm that the Earth pulls more strongly on the moon, which means that option A is the correct choice for this question.

To learn more about gravity visit:

brainly.com/question/1479537?referrer=searchResults

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Zigmanuir [339]

Answer:

it’s 2.5 m/s

Explanation:

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6 0
2 years ago
A(n)is produced around a wire when an electrical current is in the wire.
Nonamiya [84]

Answer: The correct answer is "magnetic field".

Explanation:

A magnetic field is produced around the current carrying wire.

If you bring compass needle around the current carrying wire then it shows the deflection which indicates that there is a magnetic  field around the current carrying wire.

Magnetic fields are the area around the surrounding of magnet in which magnetic force can be experienced.

Therefore, a magnetic field is produced around a wire when an electrical current is in the wire.

5 0
3 years ago
Read 2 more answers
What is the force that keeps the Earth and other planets in their orbital paths?
Anna71 [15]

Answer:

Gravity

Explanation:

Gravity is a force that pulls the surface of the earth and keeps the planets in orbits around the sun.

7 0
2 years ago
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The temperature of a smelting furnace is found to be 2000 degree Celsius.find the temperature on Fahrenheit scale​
Dima020 [189]

Answer:

3632.

Explanation:

Based on the formula:

2000×(9/5)+32=3632

6 0
2 years ago
2. A 2000 kg car with speed 12.0 m/s hits a tree. The tree does not move or
krek1111 [17]

a) The work done by the tree is -1.44\cdot 10^5 J

b) The amount of force applied is 2880 N

Explanation:

a)

According to the work-energy theorem, the work done on the car is equal to the change in kinetic energy of the car. Therefore, we can write:

W=K_f - K_i = \frac{1}{2}mv^2 - \frac{1}{2}mu^2

where

W is the work done on the car

m is the mass of the car

u is its initial speed

v is its final speed

For the car in this problem, we have:

m = 2000 kg

u = 12.0 m/s

v = 0 (since the car comes to a stop, after the crash)

Therefore, the work done by the tree on the car is:

W=0-\frac{1}{2}(2000)(12.0)^2=-1.44\cdot 10^5 J

The work is negative because it is done in the direction opposite to the direction of motion of the car.

b)

The work done by the tree on the car can also be rewritten as

W=Fd

where

F is the force applied on the car

d is the displacement of the car during the collision

In this situation, we have:

W=-1.44\cdot 10^5 J is the work done

d=50.0 cm = 0.50 m is the displacement of the car during the collision

Solving the equation for F, we find the force exerted by the tree on the car:

F=\frac{W}{d}=\frac{-1.44\cdot 10^5 J}{0.50}=-2880 N

Where the negative sign means the force is applied opposite to the direction of motion of the car. Therefore, the magnitude of the force applied is 2880 N.

Learn more about work:

brainly.com/question/6763771

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#LearnwithBrainly

3 0
3 years ago
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