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Nitella [24]
2 years ago
8

How is thermal equilibrium reached? Question 3 options: When both objects have the same temperature When objects have the same m

ass When objects are both in the same state of matter (solid, liquid, or gas) When objects have different temperatures.
Physics
1 answer:
ollegr [7]2 years ago
4 0

In the thermal equilibrium, the change in temperature is said to be zero in between the bodies. Thermal equilibrium is reached when both objects have the same temperature.

<h3>What is thermal equilibrium?</h3>

Thermal equilibrium is easily explained by the zeroth law of thermodynamics. If any two-body is at thermal equilibrium there is no change in the temperature of the body.

According to zeroth law if body A is in thermal equilibrium with body B and body B is in thermal equilibrium with C . So body A and C are also in thermal equilibrium.

In the thermal equilibrium, the net heat transfer is said to be zero in between the bodies.

Hence option A IS RIGHT. Thermal equilibrium is reached when both objects have the same temperature

To learn more about the thermal equilibrium refer to the link;

brainly.com/question/2637015

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Estimate the wavelength corresponding to maximum emission from each of the following surfaces: the sun, a tungsten filament at 2
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Applying Wein's displacement

\lamda_{max}\ T = 2898 \mu_mK

1) for sun T = 5800 K

      \lambda_{max} = \dfrac{2898}{5800}

      \lambda_{max} = 0.5 \mu_m

2) for tungsten T = 2500 K

      \lambda_{max} = \dfrac{2898}{2500}

      \lambda_{max} = 1.16 \mu_m

3) for heated metal T = 1500 K

      \lambda_{max} = \dfrac{2898}{1500}

      \lambda_{max} = 1.93 \mu_m

4) for human skin T = 305 K

      \lambda_{max} = \dfrac{2898}{305}

      \lambda_{max} = 9.50 \mu_m

5)  for cryogenically cooled metal T = 60 K

      \lambda_{max} = \dfrac{2898}{60}

      \lambda_{max} = 48.3 \mu_m

range of different spectrum

UV ----0.01-0.4

visible----0.4-0.7

infrared------0.7-100

for sun T = 5800

λ              0.01           0.4               0.7                 100

λT             58           2320            4060             5.8 x 10⁵

F                0             0.125             0.491                1

fractions

for UV = 0.125  

for visible = 0.441-0.125 = 0.366

for infrared = 1 -0.491 = 0.509  

8 0
3 years ago
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