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larisa [96]
2 years ago
6

Why is light referred to as an electromagnetic wave.

Physics
1 answer:
dangina [55]2 years ago
8 0

they have oscillating electric and magnetic fields

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Which of these is a source of voltage?
storchak [24]
D, all of these are voltage sources. A battery can power small things, generators can power larger things, and outlets can charge, or power things.
5 0
4 years ago
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Bob walks 290 m south, then jogs 630 m southwest, then walks 290 m in a direction 26 ∘ east of north.
solong [7]

whos spying on bob O.o


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3 years ago
. a boat can travel in still water. (a) if the boat points directly across a stream whose current is what is the velocity (magni
mixer [17]

a) The velocity of the boat relative to the shore is 3.40 m/s and b) The position of the boat relative to its point of origin after 3s is 10.20m.

Here it is given that the speed of the boat (x) = 2.20m/s

The speed of the stream current (y) = 1.20m/s

a) We have to find the velocity of the boat relative to the shore.

The speed of the boat = x + y

                                    = 2.20 + 1.20

                                    = 3.40m/s

b) Now we have to find the position of the boat after 3s

The formula for speed:

Speed = Distance/ Time

distance = speed × time

speed = 3.40m/s

Time = 3s

distance = 3.40 × 3

              = 10.20 m

Therefore we get a) speed as 3.40m/s and b) distance as 10.20m.

To know more about the boat and stream refer to the link given below:

brainly.com/question/382952

#SPJ4

 

8 0
1 year ago
3000 N is exerted for 4.0 seconds on a 9500 kg object.<br><br> What is the change in momentum?
WARRIOR [948]
Force is the change in momentum over a specific time. The change of momentum is therefore the force multiplied by the time that the force acts, so 3000x4.0=12000 N s=12000 kg m/s
8 0
2 years ago
As a quality test of ball bearings, you drop bearings (small metal balls), with zero initial velocity, from a height of 1.94 m i
11Alexandr11 [23.1K]

Answer:

The average acceleration of the bearings is 0.77\times10^{3}\ m/s^2

Explanation:

Given that,

Height = 1.94  m

Bounced height = 1.48 m

Time interval t=14.86\times10^{-3}\ s

Velocity of the ball bearing just before hitting the steel plate

We need to calculate the velocity

Using conservation of energy

mgh=\dfrac{1}{2}mv^2

Put the value into the formula

9.8\times1.94=\dfrac{1}{2}\times v^2

v=\sqrt{2\times9.8\times1.94}

v=6.166\ m/s

Negative as it is directed downwards

After bounce back,

We need to calculate the velocity

Using conservation of energy

mgh=\dfrac{1}{2}mv^2'

Put the value into the formula

9.8\times1.48=\dfrac{1}{2}\times v^2'

v'=\sqrt{2\times9.8\times1.48}

v'=5.38\ m/s

We need to calculate the average acceleration of the bearings while they are in contact with the plate

Using formula of acceleration

a=\dfrac{v-v'}{t}

Put the value into the formula

a=\dfrac{5.38-(-6.166)}{14.86\times10^{-3}}

a=776.98\ m/s^2

a=0.77\times10^{3}\ m/s^2

Hence,The average acceleration of the bearings is 0.77\times10^{3}\ m/s^2

6 0
3 years ago
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