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Anika [276]
3 years ago
9

The wooden block is removed from the water bath and placed in an unknown liquid. In this liquid, only one-third of the wooden bl

ock is submerged. Is the unknown liquid more or less dense than water?
Physics
1 answer:
anygoal [31]3 years ago
4 0

Answer:

1.5 g/cm^3

Explanation:

In the question i am assuming that wooden block of weight W floats with exactly one-half of its volume below the waterline.

Let ρ_{liquid} be the density of the unknown liquid , V= volume submerged

g= acceleration due to gravity

then

weight of block = \rho_{water}\times V\times g/2

when the block is in water

Also,

weight of block = \rho_{liquid}\times V\times g/3

dividing eq 1 by eq 2 we get

\rho_{liquid} = 3/2 \rho_{water}

⇒\rho_{liquid} = 3/2

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