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Anika [276]
2 years ago
9

The wooden block is removed from the water bath and placed in an unknown liquid. In this liquid, only one-third of the wooden bl

ock is submerged. Is the unknown liquid more or less dense than water?
Physics
1 answer:
anygoal [31]2 years ago
4 0

Answer:

1.5 g/cm^3

Explanation:

In the question i am assuming that wooden block of weight W floats with exactly one-half of its volume below the waterline.

Let ρ_{liquid} be the density of the unknown liquid , V= volume submerged

g= acceleration due to gravity

then

weight of block = \rho_{water}\times V\times g/2

when the block is in water

Also,

weight of block = \rho_{liquid}\times V\times g/3

dividing eq 1 by eq 2 we get

\rho_{liquid} = 3/2 \rho_{water}

⇒\rho_{liquid} = 3/2

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vovangra [49]

gravitational force of planet exerted on its object near the surface is known as weight

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So on the surface of mars the Weight of objects must be much less than the weight of object on surface of Earth

so here correct answer must be

<em>D. Your weight would decrease.</em>

6 0
3 years ago
NEED HELP ASAP<br><br>ONLY ANSWER IF YK THE ANSWERS
nalin [4]

Answer:

there yah go that's the answer

6 0
2 years ago
Magnetism/ magnetic field ana magnetic forces
katovenus [111]

Answer:

Magnetism is a physical phenomenon that manifests itself in a force acting between magnets or other magnetized or magnetisable objects, and a force acting on moving electric charges, such as in current-carrying cables. The force action takes place by means of a magnetic field, which is generated by the objects themselves or otherwise. There are natural and artificial magnets. All magnets have two poles called the north pole and the south pole. The north pole of one magnet repels the north pole of another magnet and attracts the south pole of another magnet; the same with south poles.  

6 0
3 years ago
A 1.1-kg uniform bar of metal is 0.40 m long and has a diameter of 2.0 cm. When someone bangs one end of this bar, a 1.5 MHz sho
lyudmila [28]

Answer:

\lambda = 2.22\times 10^{-3}\ m

Explanation:

Given,

mass of the bar = 1.1 Kg

length of rod, l = 0.40 m

diameter of the rod, d = 2 cm

frequency, f = 1.5 MHz

time, t = 0.12 ms

wavelength of the shock wave = ?

Speed of the wave =\dfrac{L}{t}=\dfrac{0.40}{0.12\times 10^{-3}}

   v = 3333.33 m/s

wavelength of the wave

\lambda = \dfrac{v}{f}= \dfrac{3333.33}{1.5\times 10^6}

\lambda = 2.22\times 10^{-3}\ m

6 0
2 years ago
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Dennis_Churaev [7]

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hope this helps you out!!:)))

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3 years ago
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