The molarity of 25.00 grams of powdered AgNO3 added to 500.00mL of pure water is 0.29 mol/L
<h3>Stoichiometry</h3>
From the question, we are to determine the molarity of the solution prepared.
First, we will determine the number of moles of AgNO₃ present.
Using the formula,

From the given information,
Mass = 25.00 g
Molar mass = 169.874 g/mole
Number of moles = 
Number of moles of AgNO₃ present = 0.147168 mole
Now, for the molarity of the solution

From the given information,
Volume = 500.00 mL = 0.5 L
Molarity = 
Molarity = 0.294336
Molarity ≅ 0.29 mol/L
Hence, the molarity of 25.00 grams of powdered AgNO3 added to 500.00mL of pure water is 0.29 mol/L
Learn more on Stoichiometry here: brainly.com/question/14805986