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2 years ago

How the different types of waves are form and how the waves travel

1 answer:

4 0

There are 2 types of waves mechanical and electromagnetic, mechanical waves need a medium to travel energy, while an electromagnetic wave doesn’t not require a medium. Electromagnetic waves travel through the vacuum(space). Electromagnetic waves include : radio waves, microwaves, infrared radiation, visible light, Ultraviolet light ( UV light), x-rays, and gamma rays, all of those are transverse waves. Mechanical waves are separated into 2 waves longitudinal and transverse. Transverse waves travel up and down while longitudinal waves travel back-and-forth

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4. A car is accelerating at 40 m/s2, if the car is 400 kg how much force

Ksenya-84 [330]

Sorry I’m only in kindergarten is it 10kg must be supplied???

5 0

3 years ago

What is the passenger's apparent weight at t=1.0s?

Fittoniya [83]

Answer:

For the complete question provided in explanation, if the elevator moves upward, then the apparent weight will be 1035 N. While for downward motion the apparent weight will be 435 N.

Explanation:

The question is incomplete. The complete question contains a velocity graph provided in the attachment. This is the velocity graph for an elevator having a passenger of 75 kg.

From the slope of graph it is clear that acceleration at t = 1 sec is given as:

Acceleration = a = (4-0)m/s / (1-0)s = 4 m/s^2

Now, there are two cases:

1- Elevator moving up

2- Elevator moving down

For upward motion:

Apparent Weight = m(g + a)

Apparent Weight = (75 kg)(9.8 + 4)m/s^2

<u>Apparent Weight = 1035 N</u>

For downward motion:

Apparent Weight = m(g - a)

Apparent Weight = (75 kg)(9.8 - 4)m/s^2

<u>Apparent Weight = 435 N</u>

4 0

3 years ago

Read 2 more answers

Isaac Newton's first law of motion states?

lesya [120]

Answer:

His first law states that every object will remain at rest or in uniform motion in a straight line unless compelled to change its state by the action of an external force. In other words its inertia.

Explanation:

8 0

3 years ago

Calculate the magnitude of electric field strength at a point 3cm from an infinite line of charge of linear density 18 μC/cm sit

valina [46]

Answer:

The magnitude of the electric field strength = 7.2 x 10⁸ N/C

Explanation:

The linear density:

$\begin{gathered} \lambda=18\mu C\text{ /cm} \\ \\ \lambda=\frac{18*10^{-6}C}{0.01m} \\ \\ \lambda=0.0018\text{ C/m} \end{gathered}$

Point r = 3 cm = 3/100 m

r = 0.03 m

The electric field strength is calculated below

$\begin{gathered} E=\frac{\lambda}{2\pi\epsilon_o\epsilon_rr} \\ \\ E=\frac{0.0018}{2\times3.14\times8.85\times10^{-12}\times1.5\times0.03} \\ \\ E=719709237.468\text{ N/C} \\ \\ E=7.2\times10^8\text{ N/C} \\ \end{gathered}$

The magnitude of the electric field strength = 7.2 x 10⁸ N/C

8 0

1 year ago

Atoms that emit particles and energy from their nuclei are

saw5 [17]

Atoms that emit particles and energy from their nuclei are (Radioactive).

4 0

3 years ago