220 mL of oxygen gas was collected over water. The total pressure of oxygen plus water vapor was 745.8 mmHg at 25.0°C. What is t
1 answer:
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<u>Answer:</u> The correct answer is Option b.
<u>Explanation:</u>
To calculate the amount of heat absorbed or released, we use the following equation:
.....(1)
where, q = amount of heat absorbed or released.
m = mass of the substance
c = heat capacity of water = 4.186 J/g ° C
= Change in temperature
- <u>For Trial 1:</u>
We are given:
Putting values in equation 1, we get:
q = 5023.2 J
- <u>For trial 2:</u>
We are given:
Putting values in equation 1, we get:
q = 1674.4 J
Heat gained by Trial 1 than trial 2 =
Hence, the amount of heat gained in Trial 1 about 3347 J more than the heat released in Trial 2.
Thus, the correct answer is Option b.