All categories

3 years ago

A monosaccharide is formed from a polysaccharide in what kind of reaction?.

Chemistry

1 answer:

Sever21 [200]3 years ago

7 0

Answer:

Catabolic reactions

Explanation:

Anabolic reactions combine monosaccharides to form polysaccharides, fatty acids to form triglycerides, amino acids to form proteins, and nucleotides to form nucleic acids. These processes require energy in the form of ATP molecules generated by catabolic reactions.

You might be interested in

When magnesium reacts with chlorine, magnesium ions, Mg2+, and chloride ions, Cl−are formed. In this reaction, magnesium atoms A

Slav-nsk [51]

<u>Answer:</u> In the reaction, magnesium atoms lose electrons.

<u>Explanation:</u>

An ionic compound is defined as the compound which is formed when electron gets transferred from one atom to another atom. These are usually formed when a metal reacts with a non-metal or a metal reacts with a polyatomic ion or a reaction between two polyatomic ions takes place.

Magnesium is 12th element of the periodic table having electronic configuration of $1s^22s^22p^63s^2$

This element will loose 2 electrons to form $Mg^{2+}$ ion

Chlorine is 17th element of the periodic table having electronic configuration of $1s^22s^22p^63s^23p^5$

This element will gain 1 electron to form $Cl^-$ ion

By criss-cross method, the oxidation state of the ions gets exchanged and they form the subscripts of the other ions. This results in the formation of a neutral compound.

The ionic compound formed is $MgCl_2$

Hence, in the reaction, magnesium atoms lose electrons.

5 0

4 years ago

Ag + HCl --> ?

denpristay [2]

Ag + HCI = AgCI + H2

8 0

3 years ago

HELP!! ASSIGNMENT DUE TODAY! PLEASE HELP!!! I'LL GIVE 21 POINTS!!!!

ra1l [238]

mitochondria

im not 100% sure but it makes sense

8 0

3 years ago

Equal volumes of two solutions, one containing a strong acid at pH 2 and the other containing a strong base at pH 12, are mixed.

mash [69]

Answer:

Explanation:

Assume we have 1 L of each solution.

Solution 1

$\text{[H$^{+}$]}= 10^\text{-pH} \text{ mol/L} = 10^{\text{-2}} \text{ mol/L}\\ \text{ moles of H}^{+} = \text{ 1 L solution} \times \dfrac{10^{-2}\text{ mol H}^{+}}{\text{1 L solution}} = 10^{-2}\text{ mol H}^{+}$

Solution 2

pH = 12

pOH = 14.00 - pOH = 14.00 - 12 = 2.0

$\text{[OH$^{-}$]}= 10^\text{-pOH} \text{ mol/L} = 10^{\text{-2}} \text{ mol/L}\\ \text{ moles of OH}^{-} = \text{ 1 L solution} \times \dfrac{10^{-2}\text{ mol OH}^{-}}{\text{1 L solution}} = 10^{-2}\text{ mol OH}^{-}$

3. pH after mixing

H⁺ + OH⁻ ⟶ H₂O

I/mol: 10⁻² 10⁻²

C/mol: -10⁻² -10⁻²

E/mol: 0 0

The H⁺ and OH⁻ have neutralized each other. The pH will be that of pure water.

pH = 7

8 0

4 years ago

Can someone help me with these answer becuz im struggling sorry

Bumek [7]

Answer:

21.8

Explanation:

add both because there both forces are going down

7 0

3 years ago