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Answer:
The final velocity of 18 kg ball is 
= 42.09 
Explanation:
Mass of first ball 
= 18 kg
Mass of second ball 
= 47 kg
Initial velocity of 18 kg ball 
= 76
Initial velocity of 47 kg ball = 0
Final velocity of 18 kg ball = ??
Final velocity of 18 kg ball is given by the formula
= 
Put all the values in above formula we get
= 2 × 18 × 
= 42.09
Thus, the final velocity of 18 kg ball is = 42.09
Answer:
The distance traveled by the woman is 34.1m
Explanation:
Given
The initial height of the cliff
yo = 45m final, positition y = 0m bottom of the cliff
y = yo + ut -1/2gt²
u = 20.0m/s initial speed
g = 9.80m/s²
0 = 45.0 + 20×t –1/2×9.8×t²
0 = 45 +20t –4.9t²
Solving quadratically or by using a calculator,
t = 5.69s and –1.61s byt time cannot be negative so t = 5.69s
So this is the total time it takes for the ball to reach the ground from the height it was thrown.
The distance traveled by the woman is
s = vt
Given the speed of the woman v = 6.00m/s
Therefore
s = 6.00×5.69 = 34.14m
Approximately 34.1m to 3 significant figures.
Agriculture would use fresh water
