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3 years ago

The primary colors for paints are different for those used in a television because

Physics

2 answers:

ZanzabumX [31]3 years ago

8 0

Answer:

C. Both of A and C

Explanation:

Primary colors are colors that can be combined with one another to form other colors called secondary colors.

Light can be defined as a phenomenon that causes the sensation of vision. The primary colors with regards to light are: red, green and blue. Light is a form of an additive system where there is an addition of two or more primary colored lights to form other colors.

Paints are subtractive systems that produce color due to absorption and reflection of colors. A green paint appears green because it has absorbed other colors and reflects only green. Its primary colors are blue, yellow and green.

Therefore, paints reflect light and take out light from what light is shined onto them.

ANTONII [103]3 years ago

6 0

Answer:

the correct answer is A

Explanation:

In my opinion, the colors in both visual sources are different than in a painting, the color is the wave that is refracted when perceiving it with our human eye (this means that a painting of red color, absorbs all the waves of the color ranges except the color red and that refracted wave is captured by our eye and we visualize it that way) on the other hand, on the television screen or other screens the colors have the same system that we explain with the paintings but they also have more luminosity or greater value, intensity since they emit or emit light and greater brightness.

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A Foucault pendulum consists of a brass sphere with a diameter of 31.0 cm suspended from a steel cable 11.0 m long (both measure

kozerog [31]

Answer:

43.7 °C

Explanation:

$\alpha_b$ = Coefficient of linear expansion of brass = $18\times 10^{-6}\ ^{\circ}C$

$\alpha_s$ = Coefficient of linear expansion of steel = $11\times 10^{-6}\ ^{\circ}C$

$L_{0b}$ = Initial length of brass = 31 cm

$L_{0s}$ = Initial length of steel = 11 m

$\Delta L$ = Total change in length = 3 mm

Total change in length would be

$\Delta L=\Delta L_b+\Delta L_s\\\Rightarrow \Delta L=L_{0b}\alpha_b\Delta T+L_{0s}\alpha_b\Delta T\\\Rightarrow \Delta T=\frac{\Delta L}{L_{0b}\alpha_b+L_{0s}\alpha_b}\\\Rightarrow \Delta T=\frac{0.003}{0.31\times 18\times 10^{-6}+11\times 10^{-6}\times 11}\\\Rightarrow \Delta T=23.7\ ^{\circ}C$

$\Delta T=23.7\\\Rightarrow T_f-T_i=23.7\\\Rightarrow T_f=23.7+T_i\\\Rightarrow T_f=23.7+20\\\Rightarrow T_f=43.7\ ^{\circ}C$

The final temperature is 43.7 °C

6 0

3 years ago

A bicycle wheel has a diameter of 63.0 cm and a mass of 1.75 kg. Assume that the wheel is a hoop with all of the mass concentrat

Masteriza [31]

Answer:

F2 = 834 N

Explanation:

We are given the following for the bicycle;

Diameter; d1 = 63 cm = 0.63 m

Mass; m = 1.75 kg

Resistive force; F1 = 121 N

For the sprocket, we are given;

Diameter; d2 = 8.96 cm = 0.0896 m

Radius; r2 = 0.0896/2 = 0.0448 m

Radial acceleration; α = 4.4 rad/s²

Now moment of inertia of the wheel which is assumed to be a hoop is given by; I = m(r1)²

Where r1 = (d1)/2 = 0.63/2

r1 = 0.315 m

Thus, I = 1.75 × 0.315²

I = 0.1736 Kg.m²

The torque is given by the relation;

I•α = F1•r1 - F2•r2

Where F2 is the force that must be applied by the chain to give the wheel an acceleration of 4.40 rad/s².

Thus;

0.1736 × 4.4 = (121 × 0.315) - (0.0448F2)

>> 0.76384 = 38.115 - (0.0448F2)

>> 0.0448F2 = 38.115 - 0.76384

>> F2 = (38.115 - 0.76384)/0.0448

>> F2 = 833.73 N

Approximately; F2 = 834 N

7 0

3 years ago

Which can lead to an inaccurate tympanic temperature reading?

lozanna [386]

Significant ear drainage or a scarred tympanic membrane can lead to inaccurate results on a tympanic temperature reading.

<h3>Why inaccurate tympanic temperature reading?</h3>

Significant ear drainage or a scarred tympanic membrane can lead to inaccurate results on a tympanic temperature reading.

Although an ear infection or the presence of an ear infection will not significantly affect a tympanic thermometer reading.

If the client has been sleeping on one side, take the temperature on the other side as heat may be increased on the side against the pillow.

Recent consumption of a cold beverage will not affect tympanic temperature.

To learn more about temperature readings, refer https://brainly.ph/question/20039492

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6 0

1 year ago

if your vehicle begins to slide or skid in the rear, you should? group of answer choices press the gas pedal and speed up. steer

MariettaO [177]

if your vehicle begins to slide or skid in the rear, you should steer in the direction that the rear is sliding to.

<h3>What should you do if the rear end of the vehicle starts to slide or skid?</h3>

In the case above, a person need to Look as well as steer in the direction that the person want the front of the vehicle to go.

Note that in the case above;

Do stay way from the brake pedal and never apply the brakes.

Steer in the the same direction as the rear of the vehicle that is known to be sliding. This will give room for the vehicle to go straight instead of going sideways.
Then make sure to get ready to steer in the opposite direction if the vehicle is one that begins swerving in the other direction.

Therefore, if your vehicle begins to slide or skid in the rear, you should steer in the direction that the rear is sliding to.

Learn more about slide or skid from

brainly.com/question/2148046

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1 year ago

A small 175-g ball on the end of a light string is revolving uniformly on a frictionless surface in a horizontal circle of diame

dalvyx [7]

Complete question:

A small 175-g ball on the end of a light string is revolving uniformly on a frictionless surface in a horizontal circle of diameter 1.0 m. The ball makes 2.0 revolutions every 1.0 s. What are the magnitude and direction of the acceleration of the ball?

Answer:

The acceleration of the ball is 78.98 m/s², directed inwards

Explanation:

Given;

mass of the ball, m = 175 g

radius of the circle, r = 0.5 m

angular speed of the ball, ω = 2 rev/s

The magnitude of the centripetal acceleration of the ball is calculated as follows;

$a_c = \omega^2 r\\\\where;\\\omega \ is \ angular \ speed \ in \ rad/s\\\\a_c = (2\ \frac{rev}{s} \times \frac{2\pi \ rad}{1 \ rev} )^2 \times (0.5 \ m)\\\\a_c =78.98 \ m/s^2$

The centripetal acceleration is directed inwards.

8 0

3 years ago