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krok68 [10]
2 years ago
12

Lakshmi has a sample of ammonium nitrate (NH4NO3) that has a mass of 40. 10 g. She knows that the molar mass of NH4NO3 is 80. 04

32 g/mol. To the correct number of significant digits, how many moles of NH4NO3 does the sample contain? 0. 50 moles 0. 500979 moles 0. 500980 moles 0. 5010 moles.
Chemistry
1 answer:
nexus9112 [7]2 years ago
8 0

Moles are an estimation of the smallest unit of the molecules and the atoms in a sample. The moles of ammonium nitrate in a sample are 0.5010 moles.

<h3>What are moles?</h3>

Moles are calculated by dividing the mass of the substance in gm by that of the molar mass in gram per mole.  

Given.

Mass of ammonium nitrate = 40.10 gm

The molar mass of ammonium nitrate = 80. 0432 g/mol

Moles of ammonium nitrate are calculated as:

\begin{aligned}\rm moles &= \rm \dfrac{mass}{molar\; mass}\\\\&= \dfrac{40.10}{80.0432}\\\\&= 0.5010 \;\rm mol\end{aligned}

Therefore, moles of ammonium nitrate present is option d. 0.5010 moles.

Learn more about moles here:

brainly.com/question/2396149

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Explanation:

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(b)     The given data is as follows.

               Brinell Hardness = 300

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               BHI diameter (D) = 10 mm

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                      d = \sqrt{(D^{2} - [D - \frac{2P}{HB} \pi D]^{2})}

                         = \sqrt{(10 mm)^{2} - [10 mm - \frac{2 \times 500 kg}{300 \times 3.14 \times 10 mm}]^{2}}

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Hence, the diameter of an indentation to yield a hardness of 300 HB when a 500-kg load is used is 4.46 mm.

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