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1 year ago

Suppose you have a 100 mhz cpu and a a/d converter with an 8 khz sampling rate. Samples of the a/d converter are 32-bits

Physics

1 answer:

seropon [69]1 year ago

3 0

The sampling rate that's given regarding the CPU will produce a rate of 256kps.

<h3>How to calculate the rate? </h3>

The following can be gotten from the question:

Sampling rate = 8KHx

Number of bits = 32

The data rate will be:

= 32 × 8kbps

= 256kps

In conclusion, the sampling rate that's given regarding the CPU will produce a rate of 256kps.

Learn more about rates on:

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4. 1 and 2 only.

1. the downward force is the force of gravity.

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2 years ago

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A diagram of a closed circuit with a power source on the left labeled 120 V. There are 3 resistors in parallel, separate paths,

Zina [86]

1) The equivalent resistance is $2.73\Omega$

2) The voltage in the circuit is 120 V

3) The total current in the circuit is 44.0 A

Explanation:

Resistors are said to be in parallel when they have the same potential difference at their terminals.

The formula to calculate the equivalent resistance for three resistors in parallel is:

$\frac{1}{R_T}=\frac{1}{R_1}+\frac{1}{R_2}+\frac{1}{R_3}$

where $R_1, R_2, R_3$ are the resistances of the three resistors.

In this problem, the resistance of each resistor is:

$R_1 = 5.0 \Omega$

$R_2 = 10.0 \Omega$

$R_3 = 15.0 \Omega$

Substituting,

$\frac{1}{R_T}=\frac{1}{5}+\frac{1}{10}+\frac{1}{15}=\frac{11}{30}$

So the equivalent resistance is

$R_T = \frac{30}{11}=2.73 \Omega$

In this problem we are told that the three resistors are connected in parallel. This means that their terminals are connected to the same point of the circuit: therefore, this means that they also have the same potential difference across them.

Therefore, the voltage in each branch containing each resistor is the same, and it is equal to the voltage of the battery, which is

$V=120 V$

So, the voltage in the circuit is 120 V.

The total current in the circuit can be found by using Ohm's law:

$V=RI$

where

V is the voltage

R is the equivalent resistance of the circuit

I is the current

In this circuit, we have:

V = 120 V

$R=2.73\Omega$

Re-arranging the equation for I, we find the current:

$I=\frac{V}{R}=\frac{120}{2.73}=44.0 A$

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