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Nadusha1986 [10]

2 years ago

15

Q6. Ask for two numbers. If the first one is larger than the second, display the second number first and then the first number,

otherwise show the first number first and then the second.

1 answer:

Shalnov [3]2 years ago

6 0

Answer:

Number1 = input("Choose a number: )

Number2 = input("Choose a second number: )

if number1 > number2:

print(number2\nnumber1)

else:

print(number1\nnumber2)

Explanation:

I'm assuming that you want it in python.

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Java Programming: Loops and Conditionals

velikii [3]

Answer:

import java.util.Scanner;
import java.util.Random;
public class Main {
public static void main(String[] args) {
Scanner input = new Scanner(System.in);
Random rand = new Random();
System.out.print("Enter number of questions you wish to practice: ");
int n = input.nextInt();
int i = 1;
while(i <= n){
int num1 = 1 + rand.nextInt(10);
int num2 = 1 + rand.nextInt(10);
int answer = num1 * num2;
System.out.print("Question " + i + ": " + num1 + " x " + num2 + " = ");
int response = input.nextInt();
if(response == answer){
System.out.println("Correct answer!");
}
else{
System.out.println("Wrong answer. It should be " + answer);
}
i++;
}
}
}

Explanation:

Firstly, we import Scanner and Random classes (Line 1-2) as we need to get user input for number of questions and generate random number in each question.

Next, create a Scanner and Random object (Line 7-8). Prompt user to input number of question and get the input using the Scanner object (Line 10-11).

Next create a while loop and set the condition to loop for n number of times (based on number of questions) (Line 14). In the loop, use Random object nextInt method to generate two integers between 1 -10 (Line 15-16). Prompt user to input an answer using the Scanner object (Line 18-19). If the response is matched with answer print a correct message (Line 21-22) other wise inform user they write a wrong answer and show the correct answer (Line 24-25).

8 0

4 years ago

How does sea navigation work?

ahrayia [7]

Answer:

a clock

Explanation:

you use a clock in water

3 0

3 years ago

A car engine with a thermal efficiency of 33% drives the air-conditioner unit (a refrigerator) besides powering the car and othe

fgiga [73]

Answer:

The rate of fuel required to drive the air conditioner $Q_h = 6.061 kW$

The flow rate of the cold air is $\r m = 0.30765 kg/s$

Explanation:

From this question we are told that

The efficiency is $\eta = 33$ % = 0.33

Temperature for the hot day is $T_h = 35^oC = 308 K \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ (35+273)$

Temperature after cooling is $T_c = 5^oC = 278K$

The input power is $P_{in} = 2kW$

The rate of fuel required to drive the air conditioner can be mathematically represented as

$Q_h = \frac{P_{in}}{\eta}$

$= \frac{2}{0.33} = 6.061 kW$

From the question the air condition is assumed to be half as a Carnot refrigeration unit

This can be Mathematically interpreted in terms of COP(coefficient of performance) as

$\beta_{air} = 0.5 \beta$

where $\beta$ denotes COP and is mathematically represented as

$\beta = \frac{Q_c}{P_{in}}$

= > $Q_c = \beta P_{in}$

Where $Q_c$ is the rate of flue being burned for cold air to flow

Now if the COP of a Carnot refrigerator is having this value

$\beta_{Carnot } = \frac{T_c}{T_h - T_c}$

$= \frac{278}{308-278}$

$\beta_{Carnot} = 9.267\\$

Then

$\beta_{air} = 0.5 * 9.2667$

$= 4.6333$

Now substituting the value of $\beta$ to solve for $Q_c$

$Q_c = \beta P_{in}$

$= 4.6333 *2$

$9.2667kW$

The equation for the rate of fuel being burned for the cold air to flow

$Q_c = \r mc_p \Delta T$

Making the flow rate of the cold air

$\r m = \frac{Q_c}{c_p \Delta T}$

$= \frac{9.2667}{1.004}* (308 - 278)$

$= 0.30765 kg/s$

4 0

3 years ago

Construct a Mohr circle for the stress element at A in problem 2. Using ruler and compass, draw the Mohr circle to the scale. Dr

serious [3.7K]

Answer:

hello your question is incomplete attached below is the missing diagram to the question and the detailed solution

Answer : principal stresses : 0.82 MPa, -33.492 MPa

shear stress = 17.157 MPa

∅ = 9.09 ≈ 10°

Explanation:

The principal stress ( б1 ) = 0.82 MPa

( б2 ) = -33.492 MPa

The shear stress = 17.157 MPa

∅ = 9.09 ≈ 10°

attached below is the detailed solution and the Mohr's circle

7 0

3 years ago

Which of the following is lost when the computer is turned off? ILL MARK BRAINLEST

Pavel [41]

Answer:

cloud storage is the answer

6 0

3 years ago

Read 2 more answers