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Nadusha1986 [10]
2 years ago
15

Q6. Ask for two numbers. If the first one is larger than the second, display the second number first and then the first number,

otherwise show the first number first and then the second.
Engineering
1 answer:
Shalnov [3]2 years ago
6 0

Answer:

Number1 = input("Choose a number: )

Number2 = input("Choose a second number: )

if number1 > number2:

print(number2\nnumber1)

else:

print(number1\nnumber2)

Explanation:

I'm assuming that you want it in python.

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When determining risk, it is necessary to estimate all routes of exposure in order to determine a total dose (or CDI). Recognizi
Allushta [10]

Answer:

The following are the solution to this question:

Explanation:

The Formula for calculating CDI:

\bold{CDI = \frac{C \times CR \times EF \times ED}{BW \times AT}}

_{where} \\ CDI = \text{Chronic daily Intake rate}  (\frac{mg}{kg-day})} \\\\\text{C = concentration of Toluene}\\\\\text{CR = contact rate} \frac{L}{day}\\\\\text{EF = Exposure frequency} \frac{days}{year}\\\\\text{ED = Exposure duration (in years)} = 10 \ \ years\\\\\text{BW = Body weight (kg) = 70 kg for adult}\\\\ \text{AT = average period of exposure (days) }

calculating the value of AT:

=  365 \frac{days}{year}  \times  70 \ year  \\\\ = 25550 \ days

 calculating the value of Intake based drinking:

C = 1 \ \frac{mg}{L}

CR = 2 \frac{L}{day} Considering that adult females eat 2 L of water a day,

EF = 350 \frac{days}{year} for drink

calculating the CDI value:

\to CDI = \frac{(1 \times 2 \times 350 \times 10)}{(70 \times  25550)}\\\\

             = \frac{(2 \times 3500)}{(70 \times  25550)}\\\\ = \frac{(7000)}{(70 \times  25550)}\\\\ = \frac{(100)}{(25550)}\\\\=0.00391 \frac{mg}{ kg-day}

Centered on inhalation, intake:

C = \frac{1 \mu g} { m^3} \ \ \  or \ \ \ \ 0.001  \ \ \frac{mg}{m^3}\\\\CR = 20  \frac{m^3}{day}\\\\EF = 15 \frac{min}{day}  \ \ or\ \  5475 \frac{min}{yr} \ \ \  or \ \  3.80 \frac{days}{year}\\

calculating the value of CDI:

\to CDI = \frac{(0.001 \times 20 \times 3.80 \times 10)}{(70 \times 25550)}

             = \frac{(0.76)}{(1788500)}\\\\= 4.24 \times 10^{-7} \ \ \frac{mg}{kg-day}

7 0
3 years ago
Two balls are chosen randomly from an urn containing 8 white 4 black, and orange balls. Suppose that we win $ 2 for each black b
Scorpion4ik [409]
(-2,-10,-1,-2,-3,-4)
8 0
3 years ago
Which statement about tensile stress is true? A. Forces that act perpendicular to the surface and pull an object apart exert a t
svp [43]

Answer:

A. Forces that act perpendicular to the surface and pull an object apart exert a tensile stress on the object.

Explanation:

Tensile stress is referred as a deforming force, in which force acts perpendicular to the surface and pull an object apart, attempting to elongate it.

The tensile stress is a type of normal stress, in which a perpendicular force creates the stress to an object’s surface.

Hence, the correct option is "A."

3 0
3 years ago
IM JI Suneou uo mm
Oksi-84 [34.3K]

Answer: g

Explanation:

5 0
3 years ago
Estimate the energy (head) loss a short length of a pipe conveying 300 litres of water per second and suddenly enlarging from a
Ludmilka [50]

Known :

Q = 300 L/s = 0.3 m³/s

D1 = 350 mm = 0.35 m

D2 = 700 mm = 0.7 m

g = 9.81 m/s²

Solution :

A1 = πD1² / 4 = π(0.35²) / 4 = 0.096 m²

A2 = πD2² / 4 = π(0.7²) / 4 = 0.385 m²

hL = (kL / 2g) • (U1² - U2²)

hL = (kL / 2g) • Q² (1/A1² - 1/A2²)

hL = (1 / 2(9.81)) • (0.3²) • (1/(0.096²) - 1/(0.385²))

hL = 0.467 m

5 0
3 years ago
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