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kondor19780726 [428]
2 years ago
14

The Ice and steam points of a certain thermometer are found to be 20 cm apart. What temperatureis recorded in Celsius when the l

ength of mercury theard is 5cm above the ice point mark?​
Physics
1 answer:
sergejj [24]2 years ago
6 0

The Ice and steam points of a certain thermometer are found to be 20 cm apart. What temperatureis recorded in Celsius when the length of mercury theard is 5cm above the ice point mark?
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= 1/50 = 0.02 second.

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A polarized beam of intensity Io is directed into a device consisting of two polarizers. The beam is vertically polarized, and t
timama [110]

Answer:

Explanation:

The intensity of polarised light after polarization through angle θ

I = I₀ cos²θ

Here θ = 23 for first polariser

Intensity after first polarisation

= I₀ cos²23 = .846 I₀

For second polariser θ = 90 - 23 = 67 degree

Intensity after second polarisation

= .846 I₀ cos²67 =  .13 I₀ .

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3 years ago
a generator uses loops of area 0.239 m^2, rotating 373 rad/s in a 0.0639 t magnetic field. how many loops must the coil have to
Kaylis [27]

The loops must the coil have to generate a maximum emf of 2500 will be 439.

<h3 /><h3>What is the faraday law of electromagnetic induction?</h3>

According to  Faraday's law of electromagnetic induction, the rate of change of magnetic flux linked with the coil is responsible for generating emf in the coil resulting in the flow of amount of current.

Given data;

Area,A = 0.239 m²

Angular velocity,ω=373 rad/sec

Magnetic field,B=0.0639 T

Maximum emf,E= 2500V

The formula for the maximum induced voltage is;

E{max} = N ×  B × A × ω

2500 = N × 0.639 × 0.0239 × 373

N = 438.66

N = 439 \ turns

Hence, loops must the coil have to generate a maximum emf of 2500  will be 439.

To learn more about the faraday law of electromagnetic induction refer to;

brainly.com/question/26334813

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6 0
3 years ago
In 1996, astronomers discovered an icy object beyond pluto that was given the designation 1996 tl 66. it has a semimajor axis of
antoniya [11.8K]

Answer : 2446 years.

Explanation :

Length of semi major axis is, a=84\ au= 1.496\times 10^{11}\ m

According to Kepler's third law, square of time period of an orbit is directly proportional to the cube of the semi major axis.

i.e T^2=\dfrac{4\pi^2}{GM}a^3

where G is gravitational constant

M is  mass of sun, M=1.98\times 10^{30}\ Kg

So, T^2=\dfrac{4\times (3.14)^2}{6.6\times 10^{-11}Nm^2/Kg\times 1.98\times 10^{30}\Kg}

T^2=3\times 10^{-19}\times(84\times 1.496\times 10^{11})^3

T^2=3\times 10^{-19}\times 1984415.6\times 10^{33}

T^2=59532469.8\times 10^{14}\ s

T=7715.7\times 10^7\ s

since, 1\ sec=3.17\times 10^{-8}\ years

So, orbital period is approximately 2446 years.

7 0
4 years ago
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