Answer:
a)V=18.35 m/s (South -East)
b) t =7.41 m/s
c)D= 66.70 m
Explanation:
Given that
Velocity of boat in east direction = 16 m/s
Velocity of river = 9 m/s
a)The resultant velocity V

V=18.35 m/s (South -East)
b)
We know that
Distance = Velocity x time
Lets t time takes to cross the river
136 = 18.35 x t
t =7.41 m/s
c)
The distance covered downstream
We know that
Distance = Velocity x time
t= 7.41 s
D= 7.41 x 9 m
D= 66.70 m
Answer:

Explanation:
Angular acceleration is defined by 
Angular velocity is related to the period by 
Putting all together:

Taking our initial (i) point now and our final (f) point one year later, we would have:



So for our values we have:

Where the minus sign indicates it is decelerating.
C. Eastward. Acceleration is the change in speed so it can be a positive (speeding up) or negative (slowing down) acceleration
<span>Primarily C, but depending on what's being discussed, it could be all of the above
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