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Romashka [77]
2 years ago
11

Calculate the average distances the car and the washer traveled from the top of the track. Record the averages and your qualitat

ive observation in table B of your student guide. Record what happened to the washer after the car hit the textbook. Explain whether the washer did the same thing every time.
What is the average distance the car traveled _____cm
What is the average distance the washer traveled ______cm
Chemistry
2 answers:
AnnyKZ [126]2 years ago
5 0
The correct answer is 75 cm and 200 cm long
N76 [4]2 years ago
4 0

Answer:

75 cm and 200cm

Explanation:

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Calculate the molar mass of B(NO3)3 ?​
Stella [2.4K]

The molar mass of B(NO₃)₃ - Boron nitrate : 196.822 g/mol

<h3>Further explanation</h3>

In stochiometry therein includes  

<em>Relative atomic mass (Ar) and relative molecular mass / molar mass (M)  </em>

So the molar mass of a compound is given by the sum of the relative atomic mass of Ar  

M AxBy = (x.Ar A + y. Ar B)  

The molar mass of B(NO₃)₃ - Boron nitrate :

M B(NO₃)₃ = Ar B + 3. Ar N + 9.Ar O

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7 0
3 years ago
What are the number of protons, electrons, and neutrons in Potassium
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<span><span>Number of Protons-19 </span><span>Number of Neutrons-20 </span><span>Number of Electrons-<span>19</span></span></span>
4 0
4 years ago
Read 2 more answers
How many significant figures are in 0.0233?
viva [34]

Answer:

there are 3 significant figures

Explanation:

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7 0
4 years ago
Formaldehyde is a carcinogenic volatile organic compound with a permissible exposure level of 0.75 ppm. At this level, how many
Flauer [41]

Answer : The amount of formaldehyde permissible are, 5.4\times 10^{-6}g

Explanation : Given,

Density of air = 1.2kg/m^3=1.2g/L     (1kg/m^3=1g/L)

First we have to calculate the mass of air.

\text{Mass of air}=\text{Density of air}\times \text{Volume of air}

\text{Mass of air}=1.2g/L\times 6.0L

\text{Mass of air}=7.2g

Now we have to calculate the amount of formaldehyde.

Permissible exposure level of formaldehyde = 0.75 ppm = \frac{0.75g\text{ of formaldehyde}}{10^6g\text{ of air}}

Amount of formaldehyde in 7.2 g of formaldehyde = 7.2g\times \frac{0.75g\text{ of formaldehyde}}{10^6g\text{ of air}}

Amount of formaldehyde in 7.2 g of formaldehyde = 5.4\times 10^{-6}g

Thus, the amount of formaldehyde permissible are, 5.4\times 10^{-6}g

8 0
3 years ago
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