Answer:
74.12kg/day
Explanation:
Equation of reaction for the neutralization reaction of sodium hydroxide and sulfuric acid: 2NaOH + H2SO4 yields Na2SO4 + 2H2O
Mass of sulfuric acid produced per day = 90,800kg
Percentage of sulfuric acid in wastewater = 0.1%
Mass of sulfuric acid that ends up in wastewater per day = 0.1/100 × 90,800 = 90.8kg
From the equation of reaction, 2 moles of NaOH (80kg of NaOH) is required to neutralize 1 mole of H2SO4 (98kg of H2SO4)
80kg of NaOH is required to neutralize 98kg of sulfuric acid
90.8kg of sulfuric acid would be neutralized by (90.8×80)/98kg of NaOH = 74.14kg/day of NaOH
Answer:
stop
Explanation:
it would be stop I think because then the stop is a red sign. and it says stop in it
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Answer:
import java.util.Scanner;
public class SumVectorElements
{
public static void main(String[] args)
{
final int NUM_VALS = 4;
int[] origList = new int[NUM_VALS];
int[] offsetAmount = new int[NUM_VALS];
int i = 0;
origList[0] = 40;
origList[1] = 50;
origList[2] = 60;
origList[3] = 70;
offsetAmount[0] = 5;
offsetAmount[1] = 7;
offsetAmount[2] = 3;
offsetAmount[3] = 0;
/* Your solution goes here */
// Print the Sum of each element in the origList
// with the corresponding value in the
// offsetAmount.
for (i = 0; i < NUM_VALS; i++)
{
System.out.print((origList[i] + offsetAmount[i])+" ");
}
System.out.println("");
return;
}
}
Explanation: see attachment below