You just need to find distance between two points
d=
d=6
Basically we need to add and subtract 1/2 from 1/6:
(1) 1/6 - 1/2 = 1/6 - 3/6
= -2/6
= -1/3
(2) 1/6 + 1/2 = 1/6 + 3/6
= 4/6
= 2/3
Therefor the two numbers that are located 1/2 unit from 1/6 are -1/3 and 2/3
Answer: √y
<u>Step-by-step explanation:</u>
![\sqrt[6]{y^3}=y^{\frac{3}{6}}=y^{\frac{1}{2}}=\boxed{\sqrt y}](https://tex.z-dn.net/?f=%5Csqrt%5B6%5D%7By%5E3%7D%3Dy%5E%7B%5Cfrac%7B3%7D%7B6%7D%7D%3Dy%5E%7B%5Cfrac%7B1%7D%7B2%7D%7D%3D%5Cboxed%7B%5Csqrt%20y%7D)
We will use double angle identities:
cos (5x ) = sin (10x )
cos (5x ) = 2 cos (5x ) sin ( 5x )
cos ( 5 x) - 2 cos ( 5 x ) sin ( 5x ) = 0
cos ( 5 x ) · [ 1 - 2 sin (5 x) ] = 0
cos ( 5 x ) = 0 or : 1 - 2 sin (5 x) = 0
5 x = π/2 +kπ, k∈Z sin (5 x) = 1/2
x1 = π/10 + kπ/5 5 x = π/6+2kπ , k∈ Z
5 x = 5π/6 +2kπ , k∈ Z
x 2 = π/30 +2kπ/5
x 3 = π/9 + 2kπ/5
