60 N because 98N=mg (here g= 9.8 on earth) thus mass can be calculated which is 98/9.8 = 10kg
Now,new weight with g = 6m/s^2
=m×g' (here g' is new acceleration of the new planet)
= 10×6=60N
Answer:
d. The magnitude of the work done by the earth on the satellite is non zero
Explanation:
The work done is equal to the product of the force and the distance moved in the direction of the force, the force and the distance act perpendicular to one another, therefore no work is done in the circular motion of the movement of the earth.
Answer:
Frequency, f = 1 unit
Explanation:
It is given that,
Period of the wave, T = 1 unit
We need to find the frequency of the wave. There exist an inverse relationship between period and the frequency of the wave. It is given by :
Or
f = 1 unit
So, the frequency of the wave is 1 unit. Hence, this is the required solution.
From the point of view of the northern hemisphere:
The sun starts out the year at the Spring equinox, March 21,
Right Ascension 0, Declination 0.
3 months later, Summer solstice, June 21
RA = 6 hours, Dec. = +23.5°
3 months later, Fall equinox, September 21,
RA = 12 hours, Dec. = 0
3 months later, Winter solstice, December 21,
RA = 18 hours, Dec. = -23.5°
