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lisabon 2012 [21]
2 years ago
5

Why do we use days and hours instead of hours?​

Physics
1 answer:
MA_775_DIABLO [31]2 years ago
4 0

Answer:

becuase counting by hours is more complicated. then days, to make it easier to understand instead of saying I will see you in 48 hours... its easier to understand and think to say see you in 2 days!

Explanation:

hope this helps. also we did not determine time. people from history did so... wasnt really my choice or anyones!

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If you were looking for a metalloid on the periodic table,the best place to look would be?
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Answer:

Long the step line

Explanation:

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4 years ago
Which requires more work, lifting a 10.0kg load a vertical distance of 2m or lifting a 5.0kg load a distance of 4m?
Minchanka [31]

For each load,  Work = (mass) x (gravity) x (distance .

Bigger load:      Work = (10 kg) x (9.8 m/s²) x (2 m) = 196 joules .

Smaller load:    Work = (5 kg)  x  (9.8 m/s²)  x  (4 m) = 196 joules.

The work required is equal in both cases.

The mass ratio of  2:1  is exactly balanced by
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3 years ago
Science questions!! Please help!!
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Answer:

1. b

2. c

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4. a

5. a

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3 years ago
Un objeto, que se encuentra a nivel del suelo, es lanzado verticalmente hacia arriba con una velocidad de 160 km/hr. ¿Qué altura
LiRa [457]
I don’t speak Spanish?
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3 years ago
Water initially at 200 kPa and 300°C is contained in a piston–cylinder device fitted with stops. The water is allowed to cool at
netineya [11]

Answer:

Δu=1300kJ/kg  

Explanation:

Energy at the initial state

p_{1}=200kPa\\t_{1}=300^{o}\\u_{1}=2808.8kJ/kg(tableA-5)

Is saturated vapor at initial pressure we have

p_{2}=200kPa\\x_{2}=1(stat.vapor)\\v_{2}=0.8858m^3/kg(tableA-5)

Process 2-3 is a constant volume process

p_{3}=100kPa\\v_{3}=v_{2}=0.8858m^{3}/kg\\u_{3}=1508.6kJ/kg(tableA-5)

The overall in internal energy

Δu=u₁-u₃

We replace the values in equation

Δu=u₁-u₃

=2808.8kJ/kg-1508.6kJ/kg\\=1300kJ/kg

Δu=1300kJ/kg  

3 0
3 years ago
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