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2 years ago

Why do we use days and hours instead of hours?

Physics

1 answer:

MA_775_DIABLO [31]2 years ago

4 0

Answer:

becuase counting by hours is more complicated. then days, to make it easier to understand instead of saying I will see you in 48 hours... its easier to understand and think to say see you in 2 days!

Explanation:

hope this helps. also we did not determine time. people from history did so... wasnt really my choice or anyones!

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A square coil, enclosing an area with sides 2.0 cm long, is wrapped with 2 500 turns of wire. A uniform magnetic field perpendic

Delvig [45]

Answer:

The induced voltage in the coil is 0.25 V.

Explanation:

It is given that,

Area of a square coil is 2 cm or 0.02 m

Number of turns in the wire is 2500

A uniform magnetic field perpendicular to its plane is turned on and increases to 0.25 T during an interval of 1.0 s.

We need to find the induced voltage in the coil. According to Faraday's law, the induced emf in the coil is given by the rate of change on magnetic flux. So,

$\epsilon=\dfrac{-d\phi}{dt}\\\\\epsilon=\dfrac{-d(NBA)}{dt}\\\\\epsilon=NA\dfrac{-dB}{dt}\\\\\epsilon=-2500\times (0.02)^2\times \dfrac{0.25}{1}\\\\\epsilon=-0.25\ V$

So, the induced voltage in the coil is 0.25 V.

3 0

3 years ago

The voltage applied across a given parallel-plate capacitor is doubled. How is the energy stored in the capacitor affected?

ikadub [295]

Answer:

The energy stored in the capacitor quadruples its original value.

Explanation:

The energy stored in a capacitor is given by the equation

$U=\frac{1}{2}CV^2$

where

C is the capacitance

V is the voltage across the plates

The capacitance, C, depends only on the properties of the capacitor, so it does not change when the voltage applied is changed.

Instead, in this problem the voltage applied is doubled:

V' = 2V

So the new energy stored is

$U'=\frac{1}{2}C(2V)^2=4(\frac{1}{2}CV^2)=4U$

so, the energy stored has quadrupled.

8 0

3 years ago

What is meant by the term law of conservation?

GalinKa [24]

Answer:

Explanation:

any law stating that some quantity or property remains constant during and after an interaction or process, as conservation of charge or conservation of linear momentum.

4 0

3 years ago

Read 2 more answers

an astronaut on an eva has wandered dangerously far away from the shuttle. she has also exhausted all the fuel in her jet pack.

V125BC [204]

The conservation of the momentum allows to find the result of how the astronaut can return to the spacecraft is:

Throwing the thruster away from the ship.

The momentum is defined as the product of the mass and the velocity of the body, for isolated systems the momentum is conserved. If we define the system as consisting of the astronaut and the evo propellant, this system is isolated and the internal forces become zero. Let's find the moment in two moments.

Initial instant. Astronaut and thrust together.

p₀ = 0

Final moment. The astronaut now the thruster in the opposite direction of the ship.

$m_f$ = m v + M v '

where m is propellant mass and M the astronaut mass.

As the moment is preserved.

0 = m v + M v ’

v ’= $- \frac{m}{M} \ v$

We can see that the astronaut's speed is in the opposite direction to the propeller, that is, in the direction of the ship.

The magnitude of the velocity is given by the relationship between the masses.

In conclusion, using the conservation of the momentun we can find the result of how the astronaut can return to the ship is:

Throwing the thruster away from the ship.

Learn more here: brainly.com/question/14798485

5 0

2 years ago

The parking brake on a 1200kg automobile has broken, and the vehicle has reached a momentum of 7800kg.m/s. What is the velocity

liraira [26]

Answer:

Velocity of the vehicle (v) = 6.5 m/s

Explanation:

Mass of automobile (m) = 1200 kg

Momentum of vehicle (p) = 7800 kg m/s

By using formula of momentum:

$\rm p = mv \\ \rm 7800 = 1200 \times v \\ \rm v = \frac{7800}{1200} \\ \rm v = 6.5 \: m {s}^{ - 1}$

8 0

3 years ago

Why do we use days and hours instead of hours?​

Why do we use days and hours instead of hours?