Find the area Can someone pls help me?

Mathematics

1 answer:

andrezito [222]2 years ago

8 0

If I’m correct the area is 48

You might be interested in

HELP! I'LL MARK YOU BRAINLIST

klasskru [66]

Step-by-step explanation:

are in the solution:

(3,1)

(-1,2)

(6,0)

(0,0)

are not

(-2,-1)

(0,-4)

6 0

3 years ago

The police department uses a formula to determine the

laiz [17]

9514 1404 393

Answer:

78.71 mph

Step-by-step explanation:

You're looking for the solution to ...

d = 88

0.0015r^2 +r = 88

0.0015r^2 +r -88 = 0

Using the quadratic formula*, we find ...

r = (-1 +√(1² -4(0.0015)(-88)))/(2×0.0015)

r = (-1 +√1.528)/0.003 = 0.236123/0.003 = 78.7077

The speed of the car was about 78.71 mph.

_____

* The quadratic formula will also give a negative answer of about -745 mph, which is not relevant to the situation.

8 0

2 years ago

AleksAgata [21]

$\bf ~\hspace{5em} \textit{ratio relations of two similar shapes} \\\\ \begin{array}{ccccllll} &\stackrel{\stackrel{ratio}{of~the}}{Sides}&\stackrel{\stackrel{ratio}{of~the}}{Areas}&\stackrel{\stackrel{ratio}{of~the}}{Volumes}\\ \cline{2-4}&\\ \cfrac{\stackrel{similar}{shape}}{\stackrel{similar}{shape}}&\cfrac{s}{s}&\cfrac{s^2}{s^2}&\cfrac{s^3}{s^3} \end{array}~\hspace{6em} \cfrac{s}{s}=\cfrac{\sqrt{Area}}{\sqrt{Area}}=\cfrac{\sqrt[3]{Volume}}{\sqrt[3]{Volume}} \\\\[-0.35em] \rule{34em}{0.25pt}$

$\bf \cfrac{\textit{sphere A}}{\textit{sphere B}}\qquad \stackrel{\stackrel{sides'}{ratio}}{\cfrac{1}{4}}\qquad \qquad \stackrel{\stackrel{sides'}{ratio}}{\cfrac{1}{4}}=\stackrel{\stackrel{volumes'}{ratio}}{\cfrac{\sqrt[3]{288}}{\sqrt[3]{v}}}\implies \cfrac{1}{4}=\sqrt[3]{\cfrac{288}{v}}\implies \left( \cfrac{1}{4} \right)^3=\cfrac{288}{v} \\\\\\ \cfrac{1^3}{4^3}=\cfrac{288}{v}\implies \cfrac{1}{64}=\cfrac{288}{v}\implies v=18432$