Answer is: <span>the molarity of this glucose solution is 0.278 M.
m</span>(C₆H₁₂O₆<span>) = 5.10 g.
n</span>(C₆H₁₂O₆) = m(C₆H₁₂O₆) ÷ M(C₆H₁₂O₆<span>) .
</span>n(C₆H₁₂O₆) = 5.10 g ÷ 180.156 g/mol.
n(C₆H₁₂O₆<span>) = 0.028 mol.
</span>V(solution) = 100.5 mL ÷ 1000 mL/L.
V(solution) = 0.1005 L.
c(C₆H₁₂O₆) = n(C₆H₁₂O₆) ÷ V(solution).
c(C₆H₁₂O₆) = 0.028 mol ÷ 0.1005 L.
c(C₆H₁₂O₆<span>) = 0.278 mol/L.</span>
26g --- 1 mol
56g --- X
X= 56/26 = 2,154 mol
959 ml = 959cm³ = 0,959dm³
C = n/V
C = 2,154/0,959
C = 2,246 mol/dm³
Answer:
The true statement is: Spontaneous reactions tend to lead to higher entropy.
Explanation:
The spontaneity of a reaction is linked to the value of Gibbs free energy (ΔG°). The more negative is this value, the more spontaneous is a reaction. At the same time, Gibbs free energy depends on enthalpy (ΔH°) and entropy (ΔS°), according to the following expression:
ΔG° = ΔH° - T.ΔS°
We can see that higher entropies (higher ΔS°) lead to more negative ΔG°, thus, more spontaneous reactions.
Answer :
Compound : It is a mixture of elements which are chemically bonded together in a fixed proportions.
(a) Citric acid, 
In this compound, there are three types of elements present carbon, hydrogen and oxygen. There are 6 atoms of carbon element, 8 atoms of hydrogen element and 7 atoms of oxygen element.
(b) Glycine, 
In this compound, there are four types of elements present carbon, hydrogen, nitrogen and oxygen. There are 2 atoms of carbon element, 5 atoms of hydrogen element, 1 atom of nitrogen element and 2 atoms of oxygen element.
(c) Chloroform, 
In this compound, there are three types of elements present carbon, hydrogen and chlorine. There are 1 atom of carbon element, 1 atom of hydrogen element and 3 atoms of chlorine element.
(d) Sulfur hexafluoride, 
In this compound, there are two types of elements present sulfur and fluorine. There are 1 atom of sulfur element and 6 atoms of fluorine element.