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Georgia [21]
3 years ago
11

A 2200-kg railway freight car coasts at 4.1 m/s underneath a grain terminal, which dumps grain directly down into the freight ca

r. If the speed of the loaded freight car must not go below 3.4 m/s, what is the maximum mass of grain that it can accept?
Physics
1 answer:
777dan777 [17]3 years ago
8 0

Answer:

The answer is "2.41 \times 10^3"

Explanation:

Given:  

m_i = 2000 \ kg \\\\v_i= 4.1 \ \frac{m}{s} \\\\v_f = 3.4 \ \frac{m}{s} \\

Using formula:  

\to m_iv_i = m_fv_f \\\\\to m_f= \frac{m_iv_i}{v_f}

p_i, p_f = system initial and final linear momentum.

V_i, v_f = system original and final linear pace.

m_i = original weight of the car freight.

m_f= car's maximum weight

= \frac{ 2000 \times 4.1}{3.4}\\\\= \frac{ 8.2\times 10^3}{3.4}\\\\= 2.41 \times 10^3

\boxed{m_f = 2.41 \times 10^3}

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A vacuum tube diode consists of concentric cylindrical electrodes, the negative cathode and the positive anode. Because of the a
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Answer:

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Explanation:

For this exercise we can calculate the value of the constant and the electric field produced,

Let's start by calculating the value of the constant C

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            C = 4,174 10³ V / m^{3/4}

To calculate the electric field we use the expression

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We evaluate from the lower limit x = 0 E = E₀ = 0 to the upper limit x = x, E = E

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            E = 3 / 4,174 10³   (1 / x^{1/3})

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for x = 0.110 cm

          E = 7.19 10² /∛0.11

          E = 1.5  10³ N/C

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