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Alex777 [14]
3 years ago
14

Find the quotient. The answer must be a proper fraction simplest form. 4 13 ÷ −3 16

Mathematics
1 answer:
DerKrebs [107]3 years ago
5 0

Answer:

5 or 5/1

Step-by-step explanation:

did the math, this is the result. Not sure if it's right, correct me if I'm wrong

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X + y =125<br> 5x + 8y = 775
muminat

Answer:

x=75, y = 50

Step-by-step explanation:

Solve the following system:

{x + y = 125 | (equation 1)

5 x + 8 y = 775 | (equation 2)

Swap equation 1 with equation 2:

{5 x + 8 y = 775 | (equation 1)

x + y = 125 | (equation 2)

Subtract 1/5 × (equation 1) from equation 2:

{5 x + 8 y = 775 | (equation 1)

0 x - (3 y)/5 = -30 | (equation 2)

Multiply equation 2 by -5/3:

{5 x + 8 y = 775 | (equation 1)

0 x+y = 50 | (equation 2)

Subtract 8 × (equation 2) from equation 1:

{5 x+0 y = 375 | (equation 1)

0 x+y = 50 | (equation 2)

Divide equation 1 by 5:

{x+0 y = 75 | (equation 1)

0 x+y = 50 | (equation 2)

Collect results:

Answer:  {x = 75 , y = 50

8 0
3 years ago
Read 2 more answers
The altitude of a triangle is 6 cm greater than its base .if its area is 108 cm ,find its base
xeze [42]

Area of the triangle = (1/2)*base*height

base = x

height = altitude = x+6

Area of the triangle = (1/2)*x*(x+6) = 108

(1/2)*x*(x+6) = 108

x²+6x-216 =0

(x+18)(x-12)=0

x=-18, or x=12

We can use only positive value, so x=12.

Base =12 cm.


6 0
3 years ago
Find all solutions<br> 2cos(theta)+1=0<br> write in radians in terms of pi.
Orlov [11]
<span>As we know
cos theta-1= 0 
 cos theta = 1
  Now Look at a graph of the cosine function
, and you will observe that cos theta = 1
 at the points X = 0, and X = 2pi
hope it helps</span>
7 0
4 years ago
What does n equal to in 12n + 9 = 6 - 3n
sveticcg [70]
12n+9=6-3n\ \ \ \ \ \ |Add\ 3n\ to\ each\ side\\\\&#10;15n+9=6\ \ \ \ \ |Subtract\ 9\\\\&#10;15n=-3\ \ \ \ \ |Divide\ by\ -15\\\\&#10;n=-\frac{3}{15}=\boxed{-\frac{1}{5}}
6 0
3 years ago
Can someone help me with this
stiks02 [169]
Try Desmond scientific calculator it helps me out a lot
4 0
3 years ago
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