Answer:
25 gram
Explanation:
the minimum amount of the reactant needed is equal to the mass of the product because of the law of conservation of mass ok
By increasing Atomic number
Answer:
Cu (s) + 2H₂SO₄(aq) —> CuSO₄(s) + 2H₂O (l) + SO₂(s)
Explanation:
Copper metal => Cu
Sulphuric acid => H₂SO₄
copper (II) sulfate => CuSO₄
Water => H₂O
sulfur dioxide => SO₂
The equation for the reaction between copper metal and aqueous sulfuric acid can be written as follow:
Cu + H₂SO₄ —> CuSO₄ + H₂O + SO₂
The above equation can be balance as follow:
Cu + H₂SO₄ —> CuSO₄ + H₂O + SO₂
There are 2 atoms of S on the right side and 1 atom on the left side. It can be balance by writing 2 before H₂SO₄ as shown below:
Cu + 2H₂SO₄ —> CuSO₄ + H₂O + SO₂
There are 4 atoms of H on the left side and 2 atoms on the right side. It can be balance by writing 2 before H₂O as shown below:
Cu + 2H₂SO₄ —> CuSO₄ + 2H₂O + SO₂
Thus, the equation is balanced.
Include the phase of each reactant and product, we have:
Cu (s) + 2H₂SO₄(aq) —> CuSO₄(s) + 2H₂O (l) + SO₂(s)
C4H6O3 + H2O → 2 С2Н402
Explanation:
To balance the equation
C4H6O3 + H2O → С2Н402
On the reactant side
C = 4
H = 8
O = 4
On the product side
C = 2
H = 4
O = 2
So by putting 2 on the product side to С2Н402, we can balance the equation on both the sides.
Hence, the balanced equation is
Acetic Anhydride + Water → 2 molecules of Acetic Acid
C4H6O3 + H2O → 2 С2Н402
Answer:
b) K = [PCl3] / [P][Cl2]∧(3/2)
Explanation:
- P(g) + 3/2 Cl2(g) ↔ PCl3(g)
equlibrium constant (K):
⇒ K = [PCl3] / [P].[Cl2]∧(3/2)