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solong [7]
3 years ago
6

Which organelle is the control center of the cell?

Chemistry
1 answer:
Ivenika [448]3 years ago
6 0

Answer:

nucleus

Explanation:

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rutherford's experiment with gold estimate the radius of a gold atom to be approximately 1x10^-9 cm. Suppose the radius of the n
Lemur [1.5K]
I'm am pretty sure that the answer is -2
3 0
3 years ago
Calculate the Zn conc. of Zn/Zn++ // Cl/Cl- 0.1M Emf=2.21v
Leto [7]

Answer:

Option a. = 0.01 M

Explanation:

To do this, we need to gather the data:

E = 2.21 V

[Cl⁻] = 0.1 M

And the Redox reaction taking place is the following:

Zn(s) + Cl₂(g) <-------> Zn²⁺(aq) + 2Cl⁻(aq)       Q = [Zn] [Cl]²

E° Cl⁻/Cl₂ = 1.36 V

E° Zn/Zn²⁺ = -0.76 V

According to this, the expression to use will be the Nernst equation, and we can assume we are working at 25 °C, therefore, the Nernst equation will be:

E = E° - (0.059/n) logQ

E = E° - (0.059/n) ln([Cl⁻]² * [Zn²⁺])   (1)

From there, we can solve for Zn later.

First, we need to write the semi equation of oxidation and reduction, and get the standard potential of the cell:

Zn(s) --------> Zn²⁺(aq) + 2e⁻       E₁° = 0.76 V

Cl₂(g) + 2e⁻ -----------> 2Cl⁻(aq)   E₂° = 1.36 V

---------------------------------------------------------------

Zn(s) + Cl₂(g) -------> Zn²⁺(aq) + 2Cl⁻(aq)    E° = 0.76 + 1.36 = 2.12 V

Now, let's replace in (1) and then, solve for [Zn]:

2.21 = 2.12 - (0.059/2) log ([0.1]² * [Zn])

2.21 - 2.12 = -0.0295 log (0.01[Zn])

- 0.09 / 0.0295 = log (0.01[Zn])

-3.0508 = log (0.01[Zn])

10^(-3.0508) = 0.01[Zn]

8.8961x10⁻⁴ = 0.01[Zn]

[Zn²⁺] = 0.08896 M

This value can be rounded to 0.1 M. so the correct option will be option A.

5 0
3 years ago
Question 4 (1 point)
Rainbow [258]

а о

Explanation:

 The given cation:

           (Rf₂Al₂F₃)³⁺

The oxidation number gives the extent to which a specie is oxidized in a reaction.

This number is assigned based on some rules:

  • Elements in combined state whose atoms combines with themselves have an oxidation number of zero.
  • The charge carried on simple ions gives their oxidation number.
  • Algebraic sum of all the oxidation numbers of atoms in neutral compound is zero. In an ion with more than one kind of atom, the charge on it is the oxidation number.

for the specie given;

Known:

  oxidation number of Al = +3

                                      F = -1

                          charge = +3

    let the oxidation number of Rf = k

        2k + 2(3) + 3(-1) = +3

          2k + 6 - 3 = 3

            2k = 0

              k = 0

The oxidation state of rutherfodium is 0

learn more:

Oxidation state brainly.com/question/10017129

#learnwithBrainly

8 0
3 years ago
What kind of change is a change in state of matter and why<br> Physical or chemical
Maru [420]

Answer:

physical

Explanation:

Common changes of state include melting, freezing, sublimation, deposition, condensation, and vaporization. I hope this helps. :)

6 0
3 years ago
Black and green tea have a growing body of research suggesting there are positive health benefits on because of the anti-oxidant
andrezito [222]
Keeping in mind a total ignorance of both the health benefits of these teas, and the interaction between milk and antioxidants, I believe that it is possible that milk could hinder these benefits. 

Tea is usually a hot beverage. Milk, when added to this beverage, would easily dissolve. When a solute (milk) dissolves in a solvent (tea), the chemical properties of the resulting solution can become quite distinct from both of the original substances. It seems possible that the same chemical properties of tea that make it healthy could be altered by the addition of milk. 
3 0
3 years ago
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