Answer:
Yes
Explanation:
The four outer planets are all gas giants made primarily of hydrogen and helium. They have thick gaseous outer layers and liquid interiors.
Answer:
The frequency of the phonograph record is 0.2 Hz
Explanation:
The frequency of an object moving in uniform circular motion is the number of completed cycles the object makes in a specified time period
The given parameters of the phonograph record are;
The radius of the record = 0.15 m
The number of times the phonograph record rotates, n = 18 times
The time it takes the phonograph record to rotate the 18 times, t = 90 seconds
The frequency of the phonograph record, f = (The number of times the phonograph record rotates) ÷ (The time it takes the phonograph record to rotate the 18 times)
∴ The frequency of the phonograph record, f = n/t = 18/(90 s) = 0.2 Hz
The frequency of the phonograph record = 0.2 Hz.
Specific Gravity of the fluid = 1.25
Height h = 28 in
Atmospheric Pressure = 12.7 psia
Density of water = 62.4 lbm/ft^3 at 32F
Density of the Fluid = Specific Gravity of the fluid x Density of water = 1.25 x 62.4
Density of the Fluid p = 78 lbm/ft^3
Difference in pressure as we got the differential height, dP = p x g x h dP = (78 lbm/ft^3) x (32.174 ft/s^2) x (28/12 ft) [ 1 lbf / 32.174 ft/s^2] [1 ft^2 /
144in^2]
Difference in pressure = 1.26 psia
(a) Pressure in the arm that is at Higher
P = Atmospheric Pressure - Pressure difference = 12.7 - 1.26 = 11.44 psia
(b) Pressure in the tank that is at Lower
P = Atmospheric Pressure + Pressure difference = 12.7 + 1.26 = 13.96psia
Answer:
4.16m/s²
Explanation:
According to Newtons second law;
Fm is the moving force
is the coefficient of kinetic friction between the child and the slide
m is the mass
g is the acceleration due to gravity
a is the acceleration of the child
Substitute the given values and get the acceleration as shown;
35(9.8)sin27.5 - 0.415(35)(cos27.5) = 35a
158.38-12.88 = 35a
145.49 = 35a
a = 145.49/35
a = 4.16m/s²
Hence the acceleration of the body is 4.16m/s²
35 protons are present in an element whose atomic number is 35.
<u>Explanation:
</u>
In an atom of an element, the number of protons = atomic number
Number of protons = number of electrons
Mass Number = number of protons + number of neutrons
Hence, an atom with atomic number 35 will have 35 protons.
