Question

Good evening! Can someone please answer this, ill give you brainliest and your earning 50 points. Would be very appreciated.

Answer 1

Answer:

( 6(x)² + 12(x) - 90 ) ft³

Explanation:

• deep end water: 2(x)² + 12(x) + 10

• shallow end water: 4(x)² - 100

addition problem: 2(x)² + 12(x) + 10 + 4(x)² - 100

total volume of water:

• 2(x)² + 12(x) + 10 + 4(x)² - 100

• 2(x)² + 4(x)² + 12(x) + 10 - 100

• 6(x)² + 12(x) - 90

Answer 2

Answer:

a)  $\sf total \ volume \ of \ pool= (2x^2+12x+10)+(4x^2-100) \ ft^3$

b)  $\sf total \ volume \ of \ pool =(6x^2+12x-90) \ ft^3$

Step-by-step explanation:

Given:

• volume of water in the deep end:  $\sf (2x^2+12x+10) \ ft^3$
• volume of water in the shallow end:  $\sf (4x^2-100) \ ft^3$

a)  Total volume of water = deep end volume + shallow end volume

$\implies \sf total= (2x^2+12x+10)+(4x^2-100)$

b) Simplify:

$\sf \implies 2x^2+12x+10+4x^2-100$

Collect like terms:

$\sf \implies 2x^2+4x^2+12x+10-100$

Combine like terms:

$\sf \implies 6x^2+12x-90$