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Bumek [7]
2 years ago
7

Determine the degree of ionization at pH 2.0​

Chemistry
1 answer:
Lisa [10]2 years ago
8 0

Answer:

answer in the picture above

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The isomerization reaction, ch3nc → ch3cn, is first order and the rate constant is equal to 0.46 s-1 at 600 k. what is the conce
Harlamova29_29 [7]
According to this formula :
㏑[A] /[Ao] = - Kt 
when we have Ao = 0.3 m 
and K =0.46 s^-1
t = 20min = 0.2 x 60 =12 s
So by substitution :
㏑[A] / 0.3 = - 0.46 * 12
㏑[A] / 0.3 = - 5.52
by taking e^x for both side of the equation we can get [A]
∴[A] = 0.0012 mol dm^-3
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3 years ago
What is the most massive element?
Vsevolod [243]

I believe the most massive element that is naturally occurring on Earth is uranium (U), which has a nucleus of 92 protons

8 0
4 years ago
What is the composition of the nuclei modeled by these symbols? How many protons and neutrons?
gayaneshka [121]

There are six protons and eight neutrons present in the carbon atom as shown.

<h3>What is the nucleus?</h3>

The nucleus of an atom consists of its protons and its neutrons. The protons are positively charged while the neutrons have no charge.

From the symbol of the element as shown in the question, we can see that there are six protons and eight neutrons present.

Learn more about nucleus of atoms:brainly.com/question/10658589

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6 0
2 years ago
Draw relative enthalpy diagrams showing the relationship between the enthalpy ofhydration, lattice enthalpy, and the solvation e
madam [21]

Complete Question:

The complete question is on the first uploaded image

Answer:

The solution is on the second uploaded image

Explanation:

The explanation of the above solution is on the third uploaded image.

4 0
3 years ago
Combustion vapor-air mixtures are flammable over a limited range of concentrations. The minimum volume % of vapor that gives a c
DochEvi [55]
Combustion equation of n-hexane:

2C₆H₁₄ + 19O₂ → 12CO₂ + 14H₂O

a)
Assuming we have 100 moles of air,
Oxygen = 20.9 moles
n-hexane required = 20.9/19 x 2
= 2.2 moles

LFL = Half of stoichometric amount = 2.2 / 2 = 1.1
LFL n-hexane = 1.1% 

b)
1.1 volume percent required for LFL

1.1% x 1
= 0.0011 m³ of n-hexane required
6 0
3 years ago
Read 2 more answers
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