Answer:
0.011 N-m
Explanation:
Given that
The mass of a solid cylinder, m = 30 kg
The radius of the cylinder, r = 0.18 m
The acceleration of the cylinder,
It rotates about an axis through its center. We need to find the torque acting on the cylinder. The formula for the torque is given by :
Where
I is the moment of inertia of the cylinder,
For cylinder,
So,
So, the required torque on the cylinder is 0.011 N-m.
The blood then carries oxygeb around the body which this helps us to breath around the body this process happens again
Answer:
Explanation:
Answer: Let ke = 1/2 IW^2 = 1/2 kMr^2 W^2 be Earth's rotational KE. W = 2pi/24 radians per hour rotation speed and k = 2/5 for a solid sphere M is Earth mass, r = 6.4E6 m.
Then ke = 1/2 2/5 6E24 (6.4E6)^2 (2pi/(24*3600))^2 = ? Joules. You can do the math, note W is converted to radians per second for unit consistency.
Let KE = 1/2 KMR^2 w^2 be Earth's orbital KE. w = 2pi/(365*24) radians per hour K = 1 for a point mass. Note I used 365 days, a more precise number is 365.25 days per year, which is why we have Leap Years.
Find KE/ke = 1/2 KMR^2 w^2//1/2 kMr^2 W^2 = (K/k)(w/W)^2 (R/r)^2 = (5/2) (365)^2 (1.5E11/6.4E6)^2 = 7.81E9 ANS