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Rom4ik [11]
3 years ago
9

A block of mass 3. 0 kg is hung from a spring, causing it to stretch 12 cm at equilibrium, as shown above. The 3. 0 kg block is

then replaced by a 4. 0 kg block, and the new block is released from the position shown above, at which the spring is unstretched. How far will the 4. 0 kg block fall before its direction is reversed?.
Physics
1 answer:
QveST [7]3 years ago
4 0

Answer: 32 cm

Explanation:

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An ultracentrifuge accelerates from rest to 100,000 rpm in 2.00 min. (a) what is its angular acceleration in rad/s2 ? (b) what i
MissTica

(a) The angular acceleration is given by:

\alpha=\frac{\omega_f-\omega_i}{\Delta t}

where

\omega_f is the final angular velocity

\omega_i is the initial angular velocity

\Delta t is the time interval


Let's convert the angular velocities in rad/s and the time in seconds:

\omega_f=100000 \frac{rev}{min}=100000 \frac{rev}{min} \frac{2 \pi rad/rev}{60 s/min}=10467 rad/s

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\Delta t=2.00 min \cdot 60 \frac{s}{min} = 120 s


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\alpha=\frac{10467 rad/s}{120 s}=87.2 rad/s^2


(b) The tangential acceleration is given by the product between the angular acceleration and the distance of the point from the axis of rotation. In this case, the distance is

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Answer:

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