Answer: -
¹⁰B
Explanation: -
For ⁹Be,
The atomic number is 4.
The Mass number is 9.
The number of neutrons = mass number - atomic number
= 9 - 4 = 5
For ⁹B,
The atomic number is 5.
The Mass number is 9.
The number of neutrons = mass number - atomic number
= 9-5 = 4
For ¹⁰B,
The atomic number is 5.
The Mass number is 10.
The number of neutrons = mass number - atomic number
= 10-5 = 5
For ¹⁰Be,
TThe atomic number is 4.
The Mass number is 10.
The number of neutrons = mass number - atomic number
= 10-4 = 6
For ¹²C,
The atomic number is 6.
The Mass number is 12.
The number of neutrons = mass number - atomic number
= 12-6 = 6
The correct answer to this question is letter "B) 8.4 × 10-4 M."
2CO+O2<->2CO2
-x -x +x
It started as 2CO2 so +x, then it decomposed into 2CO and O2, so-x
2CO-oxidized, O2-Oxidized, 2CO2-reduced
the easiest way is to look at the equation, so if we have some reactant and no product
A<->2C+D
-x +2x +x
so if we had product concentration, and no reactant concentration
3A<-> C+D
+3x -x-x
<span>
</span>
Answer:
4 moles
Explanation:
First, let's find the molar mass of AgCl. The molar mass of Ag is 107.87 and the molar mass of chlorine is 35.45 so the total mass is 107.87 + 35.45 = 143.32 grams per mole. Now all we need to calculate is 573.28 / 143.32 = 4 moles.
Answer:
1.008moles of iodine
Explanation:
Hello,
This question requires us to calculate the theoretical yield of I₂ or number of moles that reacted.
Percent yield = (actual yield / estimated yield) × 100
Actual yield = 1.2moles
Estimated yield = ?
Percentage yield = 84%
84 / 100 = 1.2 / x
Cross multiply and solve for x
100x = 84 × 1.2
100x = 100.8
x = 100.8/100
x = 1.008moles
1.008 moles of I₂ reacted in excess of H₂ to give 1.2 moles of HI
Answer:
930 g
Explanation:
D = m/V Multiply both sides by V
m = VD
<em>Data:
</em>
V = 372 cm³
D = 2.70 g/cm³
<em>Calculation:
</em>
m = 372 × 2.50
m = 930 g
The mass of Al is 930 g.
