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stira [4]
3 years ago
13

Determine the pressure in atm exerted by 1 mole of methane placed into a bulb with a volume of 244.6 mL at 25°C. Carry out two c

alculations: in the first calculation, assume that methane behaves as an ideal gas; in the second calculation, assume that methane behaves as a real gas and obeys the van der Waals equation
Chemistry
1 answer:
Nuetrik [128]3 years ago
3 0

The pressure in atm exerted by 1 mole of methane placed into a bulb with a volume of 244.6 mL at 25°C is 101.94atm.

<h3>How to calculate pressure?</h3>

The pressure of an ideal gas can be calculated using the following formula:

PV = nRT

Where;

  • P = pressure
  • V = volume
  • n = number of moles
  • R = gas law constant
  • T = temperature

According to information in this question;

  • T = 25°C = 25 + 273 = 298K
  • V = 244.6mL = 0.24L
  • R = 0.0821 Latm/Kmol

P × 0.24 = 1 × 0.0821 × 298

0.24P = 24.47

P = 24.47/0.24

P = 101.94atm

Therefore, the pressure in atm exerted by 1 mole of methane placed into a bulb with a volume of 244.6 mL at 25°C is 101.94atm.

Learn more about pressure at: brainly.com/question/11464844

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Hope this helps, have a great day ahead!
3 0
3 years ago
How many moles of oxygen must be placed
umka21 [38]

Answer: 0.245 moles of oxygen must be placed in the container to exert the given pressure at the given temperature. The Ideal Gas Law equation gives the relationship among the pressure, volume, temperature, and moles of gas.

Further Explanation:

The Ideal Gas Equation is:  

PV = nRT  

where:  

P - pressure (in atm)  

V - volume (in L)  

n - amount of gas (in moles)  

R - universal gas constant 0.08206 \frac{L-atm}{mol-K}  

T - temperature (in K)  

In the problem, we are given the values:  

P = 2.00 atm (3 significant figures)

V = 3.00 L  (3 significant figures)

n = ?

T = 25.0 degrees Celsius (3 significant figures)  

We need to convert the temperature to Kelvin before we can use the Ideal Gas Equation. The formula to convert from degree Celsius to Kelvin is:  

Temperature \ in \ Kelvin = Temperature\ in \ Celsius \ + \ 273.15  

Therefore, for this problem,  

Temperature\ in \ K = 25.0 +273.15\\Temperature\ in \ K = 298.15  

Solving for n using the Ideal Gas Equation:  

n \ = \frac{PV}{RT}\\n \ = \frac{(2.00 \ atm) \ (3.00 \ L)}{(0.08206 \ \frac{L-atm}{mol-K})( 298.15 \ K)}  \\n \ = 0.245 \ mol

The least number of significant figures is 3, therefore, the final answer must have only 3 significant figures.

Learn More  

1. Learn more about Boyle's Law brainly.com/question/1437490  

2. Learn more about Charles' Law brainly.com/question/1421697  

3. Learn more about Gay-Lussac's Law brainly.com/question/6534668

Keywords: Ideal Gas Law, Volume, Pressure

4 0
3 years ago
Which of the following compounds has the highest boiling point?1. F22. NaF3. HF4. ClF
sergey [27]

Answer:

HF

Explanation:

Hf has hydrogen bonding which is the strongest intermolecular forces. The stronger the IM forces, the higher the boiling point.

7 0
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Can someone help me answer this
Ostrovityanka [42]

Answer:sorry

Explanation:

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Giving 30 points!! please help &lt;3
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Answer:

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Explanation:

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