Explanation:
Let us assume that the solution contains both and which has a cell voltage of 0.719 V.
Therefore, voltage of cell contains both Ag/AgCl reference electrode where electrode is 0.719 V.
As, = 0.719 V
It is known that potential of the silver-silver chloride reference electrode is 0.197 V.
Hence, = 0.197 V. Now, calculate as follows.
= 0.719 V
= 0.719 V
= 0.916 V
Now, voltage of the cell that contains both calomel reference electrode and electrode as follows.
= calomel electrode = 0.241 V
Voltage of cell =
= 0.916 V - 0.241 V
= 0.675 V
Thus, we can conclude that 0.675 V is the new voltage.
The reaction quotient will be half of the equilibrium constant of the system.
<h3>Equilibrium constant</h3>
The term equilibrium constant refers to a number that shows the extent to which reactants are converted to products when the reaction has attained equilibrium. If the system is not at equilibrium, the number is called the reaction quotient.
If the reaction system is diluted to about twice its original volume, it follows that the reaction quotient will be halved with respect to the equilibrium constant hence the most likely value of the equilibrium constant is about half of the equilibrium constant.
Learn more about equilibrium constant: brainly.com/question/17960050
Answer:
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The ksp value for calcium hydroxide at this temperature is 5.20 × 10⁻⁶.
<h3>What is ksp?</h3>
Ksp is an equilibrium constant of a solid substance dissolved in a liquid solution.
Given that, the volume of water is 0.178 l, 0.264 g of Ca(OH)² dissolves in enough water
The solution equilibrium is
Ca(OH)² = Ca + 2OH
The molar solubility is
0.186 / 74.00 / 0.230 = 0.0109 M
The ksp value will be
Ksp = (s) (2S)²
Putting the values in the formula
(0.0109) x (2 x 0.0109)² = 5.20 × 10⁻⁶.
Thus, the ksp value for calcium hydroxide is 5.20 × 10⁻⁶.
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