Answer:
oxidized
Explanation:
Each sodium atom loses an electron to form a sodium ion.
Ba(OH)2 is an basic solution. It has more OH- ions than H+ ions. pOH should be calculated to find out its pH
The reaction is
Ba(OH)2 ⇒ Ba2+ (aq) + 2 OH-(aq)
One mole barium hydroxide releases 2 moles hydroxide ions.
Use that ratio to calculate molarity (M) of OH- ions [OH-]. The ratio is 1:2.
0.10 M Ba(OH)2 release 2*0.10 M= 0.02 M OH- ions
[OH-]= 0.02
pOH= - log [OH-] = - log 0.02 = 1.7
Thats not the answer! We found pOH of the solution before titration.
pH and pOH relationship is shown by formula of pH+pOH= 14
pH= 14-pOH
pH= 14-1.7= 12.3
Well..... it would be a mechanical mixture because you use mechanical energy when you squeeze it and the mixture is the juice and the pulp.
I’m pretty sure the answer is D!
The given question is incomplete. The complete question is ;
A student dissolves of 15 g aniline in 200 ml of a solvent with a density of 1.05 g/ml. The student notices that the volume of the solvent does not change when the aniline dissolves in it. Calculate the molarity and molality of the student's solution. Be sure each of your answer entries has the correct number of significant digits.
Answer: The molarity is 0.81 M and molality is 0.82 m
Explanation:
Molarity of a solution is defined as the number of moles of solute dissolved per Liter of the solution.

where,
n= moles of solute
= volume of solution in ml = 200 ml

Now put all the given values in the formula of molarity, we get

Thus molarity is 0.81 M
Molality of a solution is defined as the number of moles of solute dissolved per kg of the solvent.

where,
n = moles of solute
= weight of solvent in g

Mass of solution = 
mass of solvent = mass of solution - mass of solute = (210 - 15) g = 195 g
Now put all the given values in the formula of molality, we get

Therefore, the molality of solution is 0.82m