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3 years ago

List examples of two energy transformations- one produced by an electric and the other by a mobile phone.

Physics

1 answer:

Phantasy [73]3 years ago

3 0

Answer:

an electric or landline turns electricity into mechanical energy while a mobile phone turns electricity to chemical to heat

Explanation:

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At an amusement park there is a ride in which cylindrically shaped chambers spin around a central axis. People sit in seats faci

ozzi

Answer:

$r=2.4m$

Explanation:

We have to use the centripetal force equation

$Fc=\frac{mv^{2} }{r}$

we need the radious so we have to isolate "r" and we get

$r=\frac{mv^{2} }{Fc}$

replacing m=65 kg, v= 4.1 m/s and Fc=455N we get

$r=\frac{65*4.1^{2} }{455}$

$r=2.4m$

The radius of the amusement park chamber is 2.4m

4 0

2 years ago

What is the SI unit for momentum?

Whitepunk [10]

Kg . Meter per second (Kg.m/s)

8 0

3 years ago

Read 2 more answers

How much work (in J) is done against the gravitational force on a 3.9 kg briefcase when it is carried from the ground floor to t

katrin2010 [14]

Answer:

W = 14523.6 J

Explanation:

Given,

Mass = 3.9 Kg

Vertical height , h = 380 m

Work done against gravitational force

W = m g h

g is acceleration due to gravity

W = 3.9 x 9.8 x 380

W = 14523.6 J

Hence, the work done by the gravitational force is equal to W = 14523.6 J

3 0

2 years ago

The height of the empire state building is 318 m if a stone is dropped from the top of the building what is the stones velocity

lutik1710 [3]

79 m/s. A stone dropped from the top of the Empire State Building will have a velocity of 79 m/s just before it strikes the ground.

This problem is about free fall, to find the velocity of the stone before it strikes the ground we have to use the equation $v_{f}^{2}=v_{0}^{2}+2gh$ , the initial velocity of the stone is 0 m/s. Then:

$v_{f}^{2}=2gh$

$v_{f}=\sqrt{ 2gh}$

Solving the equation above with g = 9.8 m/s², and h = 318.0 m:

$v_{f}=\sqrt{ 2(9.8m/s^{2})(318.0m)}= 78.95 m/s$

$v_{f}$ ≅ 79 m/s

4 0

2 years ago

A centripetal force of 210 N acts on a 1,600-kg satellite moving with a speed of 5,500 m/s in a circular orbit around a planet.

Dafna1 [17]

Answer:

Explanation:

Step one:

given

Force F= 210N

mass m= 1600kg

velocity v=5500m/s

Step two

Required is the radius r

the expression for the force is

$F_c = \frac{mv^2}{r}$

substitute

210=1600*5500^2/r

cross multiply we have

210r=48400000000

divide both side by 210

r=230476190.476m

r=230476.19km

4 0

3 years ago