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erma4kov [3.2K]
3 years ago
14

Why are scientific models important?

Physics
1 answer:
Wittaler [7]3 years ago
5 0

Answer:

Scientific models are representations of objects, systems or events and are used as tools for understanding the natural world. Models use familiar objects to represent unfamiliar things. Models can help scientists communicate their ideas, understand processes, and make predictions.

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Fossil fuels are non-renewable resources and create greenhouse gases.  While cheaper now to  burn fossil fuels, within fifty years we will run out and have to turn to other sources of energy.  Hope this helps!!!
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What component of Star Wars is possible
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___ charges attract each other
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3 years ago
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A wheel initially spinning at wo = 50.0 rad/s comes to a halt in 20.0 seconds. Determine the constant angular acceleration and t
Irina-Kira [14]

Answer:

part (a) \alpha\ =\ -2.5\ rad/s^2

part (b) N = 79.61 rev

part (c) \tau\ =\ 23.54\ Nm

Explanation:

Given,

  • Initial speed of the wheel = w_o\ =\ 50.0\ rad/s
  • total time taken = t = 20.0 sec

part (a)

Let \alpha be the angular acceleration of the wheel.

Wheel is finally at the rest. Hence the final angular speed of the wheel is 0.

\therefore w_f\ =\ w_0\ +\ \alpha t\\\Rightarrow \alpha\ =\ -\dfrac{w_0}{t}\\\Rightarrow \alpha\ =\ -\dfrac{50}{20}\\\Rightarrow \alpha\ =\ -2.5\ rad/s^2

part (b)

Let \theta be the total angular displacement of the wheel from initial position till the rest.

\therefore \theta\ =\ w_0t\ +\ \dfrac{1}{2}\alphat^2\\\Rightarrow \theta\ =\ 50\times 20\ -\ 0.5\times 2.5\times 20^2\\\Rightarrow \theta\ =\ 500\ rad

We know,  1 revolution = 2\pi rad

Let N be the number of revolution covered by the wheel.

\therefore N\ =\ \dfrac{\theta}{2\pi}\\\Rightarrow N\ =\ \dfrac{500}{2\times 3.14}\\\Rightarrow N\ =\ 79.61\ rev

Hence the 79.61 revolution is covered by the wheel in the 20 sec.

part (c)

Given,

  • Mass of the pole = m = 4 kg
  • Length of the pole = L = 2.5 m
  • Angle of the pole with the horizontal axis = \theta\ =\ 60^o

Now the center of mass of the pole = d\ =\ \dfra{L}{2}\ =\ \dfrac{2.5}{2}\ =\ 1.25\ m

Weight component of the pole perpendicular to the center of mass = F\ =\ mgcos\theta

\therefore \tau\ =\ F\times d\\\Rightarrow \tau\ =\ 4\times 9.81\times cos60^o\times 1.25\\\Rightarrow \tau\ =\ 23.54\ Nm

3 0
3 years ago
A car goes up an incline that makes an angle of 20 degrees with the horizontal. If the car has a mass of 1600 kg, and the engine
stepan [7]

Answer:

V = 5.96 m/s

Explanation:

First we find the force required to move the car up the inclined plane. This force shall be equal to the component of the weight of the car that is parallel to the inclined plane. Hence,

F = W Sin θ

F = mg Sin θ

where,

F = Force = ?

m = mass of car = 1600 kg

g = 9.8 m/s²

θ = Inclination Angle = 20°

Therefore,

F = (1600 kg)(9.8 m/s²) Sin 20°

F = 5362.87 N

Now, we use power formula:

P = FV

V = P/F

where,

P = Engine Power = 32000 W

V = Maximum Velocity of Car = ?

Therefore,

V = 32000 W/5362.87 N

<u>V = 5.96 m/s</u>

7 0
3 years ago
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