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Alina [70]
2 years ago
8

Use the table to answer the question.

Physics
1 answer:
siniylev [52]2 years ago
7 0

Answer:

Jupiter is by far the largest.

G = K M / R^2 = K C M     since R is given as 5E5 km

G = gravitational attraction

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-- The area under a velocity/time graph, between two points in time, is the difference in displacement during that period of time.

-- The area under a speed/time graph, between two points in time, is the distance covered during that period of time.

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Which of the following refers to a force acting toward the center of a circular
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Answer:

D. Centripetal Force :)

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A centrifugal pump discharges 300 gpm against a head of 55 ft when the speed is 1500 rpm. The diameter of the impeller is 15.5 i
Ksivusya [100]

Answer: Question 1: Efficiency is 0.6944

Question 2: speed of similar pump is 2067rpm

Explanation:

Question 1:

Flow rate of pump 1 (Q1) = 300gpm

Flow rate of pump 2 (Q2) = 400gpm

Head of pump (H)= 55ft

Speed of pump1 (v1)= 1500rpm

Speed of pump2(v2) = ?

Diameter of impeller in pump 1= 15.5in = 0.3937m

Diameter of impeller in pump 2= 15in = 0.381

B.H.P= 6.0

Assuming cold water, S.G = 1.0

eff= (H x Q x S.G)/ 3960 x B.H.P

= (55x 300x 1)/3960x 6

= 0.6944

Question 2:

Q = A x V. (1)

A1 x v1 = A2 x V2. (2)

Since A1 = A2 = A ( since they are geometrically similar

A = Q1/V1 = Q2/V2. (3)

V1(m/s) = r x 2π x N(rpm)/60

= (0.3937x 2 x π x 1500)/2x 60

= 30.925m/s

Using equation (3)

V2 = (400 x 30.925)/300

= 41.2335m/s

To rpm:

N(rpm) = (60 x V(m/s))/2 x π x r

= (60 x 41.2335)/ 2× π × 0.1905

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6 0
3 years ago
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What’s the answer to this question
alexgriva [62]

Answer:

space = 66.24 [m]

Explanation:

To solve this problem we must remember that the average speed is defined as the relationship between a space traveled over a certain time.

Av = \frac{space}{time}

where:

space [m]

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time = 18.4 [s]

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