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hoa [83]
2 years ago
13

A solution was found to have a 15.6 % transmittance at 500 nm, its wavelength of maximum absorption, using a cell with a path le

ngth of 5.00 cm. Calculate the absorbance of the solution in a 1.00 cm cell at 500 nm. A. 0.161 B. 69.0 C. 0.0312 D. 4.04
Chemistry
1 answer:
Gnesinka [82]2 years ago
7 0

For the absorbance of the solution in a 1.00 cm cell at 500 nm  is mathematically given as

A’ = 0.16138

<h3>What is the absorbance of the solution in a 1.00 cm cell at 500 nm?</h3>

Absorbance (A) 2 – log (%T) = 2 – log (15.6) = 0.8069

Generally, the equation for the Beer’s law is mathematically given as

A = ε*c*l

0.8069 = ε*c*(5.00 )

ε*c = 0.16138 cm-1

then for when ε*c is constant

l’ = 1.00

A’ = (0.16138 cm-1)*(1.00 cm)

A’ = 0.16138

In conclusion, the absorbance of the solution in a 1.00 cm cell at 500 nm is

A’ = 0.16138

Read more about Wavelength

brainly.com/question/3004869

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Noble Gases is the answer (please give me brainliest
4 0
3 years ago
An unknown liquid has a mass of 30.8 g, and a volume of 31.5 mL. What is the density of this liquid?
julsineya [31]

The density of the liquid is 0.98 g/mL

<h3>What is density? </h3>

The density of a substance is defined as the mass of the subtance per unit volume of the substance. Mathematically, it can be expressed as:

Density = mass / volume

With the above formula, we can obtain the density of the liquid.

<h3>How to determine the density </h3>
  • Mass = 30.8 g
  • Volume = 31.5 mL
  • Density =?

Density = mass / volume

Density of liquid = 30.8 / 31.5

Density of liquid = 0.98 g/mL

Learn more about density:

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3 0
2 years ago
What questions, if we were to answer them, would
Margarita [4]

Answer:

When our bodies are dry and wind blows by, we lose some energy to the air molecules. When are bodies are wet, we have a substance on our skin that likes to absorb heat. So when wind blows by, we lose a LOT of energy to the air molecules. When the body loses heat energy, our body temperature drops.

Explanation:

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7 0
3 years ago
1 Calcium carbonate breaks down on heating to produce calcium oxide and carbon dioxide gas.
Alborosie

Answer:  See below

Explanation:

1.  a)  0.15 moles calcium carbonate  (15g/100g/mole)

   b)  0.15 moles CaO  (molar ratio of CaO to CaCO3 is 1:1)

   c)   8.4 grams CaO  (0.15 moles)*(56 grams/mole)

2. a)  0.274 moles Na2O  (17g/62 grams/mole)

   b)  46.6 grams NaNO3  (2 moles NaNO3/1 mole Na2O)*(0.274 moles Na2O)*(85 g/mole NaNO3)

7 0
3 years ago
A 2.912 g sample of a compounds containing only C, H, and O was completely oxidized in a reaction that yielded 3.123 g of water
Taya2010 [7]

Answer:

Explanation:

18 gram of water contains 2 g of hydrogen

3.123 gram of water will contain 2 x 3.123 / 18 = .347 g of hydrogen .

44 gram of carbon dioxide contains 12 g of carbon

7.691 gram of carbon dioxide will contain 12 x 7.691 / 44 = 2.1 g of carbon .

So the sample will contain 2.912 - ( .347 + 2.1 ) g of oxygen .

= .465 g of oxygen .

moles of Carbon = 2.1 / 12 = .175

moles of hydrogen = .347 / 1 = .347

moles of oxygen = .465 / 16 = .029

Ratio of moles of carbon , oxygen and hydrogen ( C,O,H )

= 0.175 : 0.029 : 0.347

= .175/ .029 : 1 : .347 / .029

= 6 : 1 : 12

So empirical formula = C₆H₁₂O

Let the molecular formula be (C_6H_{12}O)_n

molecular weight = n ( 6 x 12 + 12x 1 + 16)

= 100 n

Given 100 n = 100.1

n = 1

Molecular formula = C₆H₁₂O.

3 0
3 years ago
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