Each shell contains a fixed number of electrons. The general formula of the number of electrons can be hold in n-th shell is 2n². 5th shell can hold 2x5² = 50 number of electrons.
1st shell contains 2 X 1²= 2 number of electrons, 2nd shell contains 2 X 2²=8 number of electrons, 3rd shell contains 2 X 3²=18 number of electrons, 4th shell contains 2 X 4²=32 number of electrons, 5th shell contains 2 X 5²=50 number of electrons and so on.
All of those quantities contain the same number of particles, since they are all two moles (or 1.204*10^24 particles).
It's similar to asking which one is heavier: a pound of brick, or a pound of feathers. Since they are both one pound, they will weigh the same.
Hope that helped! :)
Answer:
![\boxed{\text{53.3 \%}}](https://tex.z-dn.net/?f=%5Cboxed%7B%5Ctext%7B53.3%20%5C%25%7D%7D)
Explanation:
MM: 2.016 17.03
N₂ + 3H₂ ⟶ 2NH3
m/g: 26.3
1. Theoretical yield
(a) Moles of H₂
![\text{Moles of H${_2}$} = \text{26.3 g H${_2}$} \times \dfrac{\text{1 mol H${_2}$}}{\text{2.016 g H${_2}$}} = \text{13.05 mol H${_2}$}](https://tex.z-dn.net/?f=%5Ctext%7BMoles%20of%20H%24%7B_2%7D%24%7D%20%3D%20%5Ctext%7B26.3%20g%20H%24%7B_2%7D%24%7D%20%5Ctimes%20%5Cdfrac%7B%5Ctext%7B1%20mol%20H%24%7B_2%7D%24%7D%7D%7B%5Ctext%7B2.016%20g%20H%24%7B_2%7D%24%7D%7D%20%3D%20%5Ctext%7B13.05%20mol%20H%24%7B_2%7D%24%7D)
(b) Moles of NH₃
![\text{Moles of NH${_3}$} = \text{13.05 mol H${_2}$} \times \dfrac{\text{2 mol NH${_3}$}}{\text{3 mol H${_2}$}} = \text{8.697 mol NH${_3}$}](https://tex.z-dn.net/?f=%5Ctext%7BMoles%20of%20NH%24%7B_3%7D%24%7D%20%3D%20%5Ctext%7B13.05%20mol%20H%24%7B_2%7D%24%7D%20%5Ctimes%20%5Cdfrac%7B%5Ctext%7B2%20mol%20NH%24%7B_3%7D%24%7D%7D%7B%5Ctext%7B3%20mol%20H%24%7B_2%7D%24%7D%7D%20%3D%20%5Ctext%7B8.697%20mol%20NH%24%7B_3%7D%24%7D)
(c) Theoretical yield of NH₃
![\text{Mass of NH${_3}$} = \text{8.967 mol NH${_3}$} \times \dfrac{\text{17.03 g NH${_3}$}}{\text{1 mol NH${_3}$}} = \text{148.1 g NH${_3}$}](https://tex.z-dn.net/?f=%5Ctext%7BMass%20of%20NH%24%7B_3%7D%24%7D%20%3D%20%5Ctext%7B8.967%20mol%20NH%24%7B_3%7D%24%7D%20%5Ctimes%20%5Cdfrac%7B%5Ctext%7B17.03%20g%20NH%24%7B_3%7D%24%7D%7D%7B%5Ctext%7B1%20mol%20NH%24%7B_3%7D%24%7D%7D%20%3D%20%5Ctext%7B148.1%20g%20NH%24%7B_3%7D%24%7D)
(d) Percent yield
![\text{Percent yield} = \dfrac{\text{ actual yield}}{\text{ theoretical yield}} \times 100 \% = \dfrac{\text{79.0 g}}{\text{148.1 g}} \times 100 \% = \textbf{53.3 \%}\\\\\text{The percent yield is }\boxed{\textbf{53.3 \%}}](https://tex.z-dn.net/?f=%5Ctext%7BPercent%20yield%7D%20%3D%20%5Cdfrac%7B%5Ctext%7B%20actual%20yield%7D%7D%7B%5Ctext%7B%20theoretical%20yield%7D%7D%20%5Ctimes%20100%20%5C%25%20%3D%20%5Cdfrac%7B%5Ctext%7B79.0%20g%7D%7D%7B%5Ctext%7B148.1%20g%7D%7D%20%5Ctimes%20100%20%5C%25%20%3D%20%5Ctextbf%7B53.3%20%5C%25%7D%5C%5C%5C%5C%5Ctext%7BThe%20percent%20yield%20is%20%7D%5Cboxed%7B%5Ctextbf%7B53.3%20%5C%25%7D%7D)
Answer:
Option B, When the cell needs to move a compound against its concentration gradient.
Explanation:
A cell uses active transport when it has to transport substances against the concentration gradient across its membrane.
In active transport additional energy is used (generally provided by energy molecules like ATP) to push the substance across any membrane from low concentration side to high concentration side.
Option B is correct