A total charge of Q coulomb is uniformly distributed along a rod 40cm in length.find find the electric field intensity 20cm away

Question

VladimirAG [237]

2 years ago

5

A total charge of Q coulomb is uniformly distributed along a rod 40cm in length.find find the electric field intensity 20cm away

from the rod along its perpendicular bisector?

Physics

1 answer:

Tatiana [17] · Answer 1 · 2023-03-22T23:40:43+03:00

For a total charge of Q coulomb is uniformly distributed along a rod 40cm in length, the electric field intensity 20cm away from the rod is mathematically given as

E1=1.598*10^11v/m

<h3>What is the electric field intensity 20cm away from the rod along its perpendicular bisector?</h3>

Generally, the equation for the initial electric field intensity is mathematically given as

$dEp=\int{kd/r}cosd\theta$

Therefore

$e1=kd/r{sin\theta2+sinR1}$

Hence

$E1=(9*10^9/20*10^{-2})({sin45+sin45})*B/40*10^-2$

E1=B*9*10^{13})/(10*110)* $\sqrt{2}$

E1=1.598*10^11v/m

In conclusion, the electric field intensity

E1=1.598*10^11v/m