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3 years ago

A 5.5 kg box is pushed across the lunch table. The net force applied to the box is 9.7N. What is the acceleration of the box?

Physics

1 answer:

12345 [234]3 years ago

8 0

Answer:

1.76 m/s^2

Explanation:

mass of box, m = 5.5kg

net force , F = 9.7N

acceleration = ?

F = m x a

a = F/m = 9.7/5.5

a = 1.76 m/s^2

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For the sign show, select the statements below that describe the situation. Choose all that apply. The system is in equilibrium

horrorfan [7]

Answer:

A and D

Explanation:

I believe it is A and D because they appear to be the most accurate answers.

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3 years ago

The least penetrating form of radiation is ____. a. beta radiation c. alpha radiation b. gamma radiation d. X rays

svet-max [94.6K]

C) alpha radiation seems to be the answer

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3 years ago

Read 2 more answers

what volume of alcohol will have the same mass as 4.2m^3 of petrol? (density of alcohol 0.4kg/m^3 and petrol is 0.3kg/m^3)

Alexxx [7]

Answer:

3.15m³

Explanation:

To solve this problem, let us first find the mass of the petrol from the given dimension.

Mass = density x volume

Volume of petrol = 4.2m³

Density of petrol = 0.3kgm⁻³

Mass of petrol = 4.2 x 0.3 = 1.26kg

So;

We can now find the volume of the alcohol

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7 0

3 years ago

A zebra starts from rest and accelerates at 1.9 m/s2 what will be the acceleration after 5 seconds

Alex73 [517]

Answer:

d = 23.75 m

The zebra has gone 23.75m after 5 seconds.

Corrected question;

A zebra starts from rest and accelerates at 1.9 m/s2. How far has the zebra gone after 5 seconds.

Explanation:

From the equation of motion;

d = vt + 0.5at^2 .........1

Where;

d = displacement

v = initial velocity = 0

t = time taken= 5 seconds

a = acceleration = 1.9 m/s^2

Substituting the given values into equation 1;

d = 0(5) + 0.5(1.9×5^2)

d = 0.5(1.9×5^2)

d = 23.75 m

The zebra has gone 23.75m after 5 seconds.

3 0

4 years ago

In some applications of ultrasound, such as its use on cranial tissues, large reflections from the surrounding bones can produce

worty [1.4K]

Answer:

b. 0.75 mm

Explanation:

The distance between antinodes d is half the wavelength $\lambda$ . We can obtain the wavelength with the formula $v=\lambda f$ , where f is the frequency given ( $f=1MHz=1\times10^6Hz$ ) and v is the speed of sound in body tissues (v=1540m/s), so putting all together we have:

$d=\frac{\lambda}{2}=\frac{v}{2f}=\frac{1540m/s}{2(1\times10^6Hz)}=0.00077m=0.77mm$

which is very close to the 0.75mm option.

4 0

4 years ago