Answer:
Frequencia = 1.25 Hz
Explanation:
<u>Dados los siguientes datos;</u>
- Velocidad = 50 m/s
- Longitud de onda = 40 metros
Para encontrar la frecuencia de la onda;
Matemáticamente, la velocidad de una onda viene dada por la fórmula;

Haciendo de la frecuencia el tema de la fórmula, tenemos;

Sustituyendo en la fórmula, tenemos;

<em>Frequencia = 1.25 Hz</em>
Answer:
aₓ = 0
, ay = -6.8125 m / s²
Explanation:
This is an exercise that we can solve with kinematics equations.
Initially the rabbit moves on the x axis with a speed of 1.10 m / s and after seeing the predator acceleration on the y axis, therefore its speed on the x axis remains constant.
x axis
vₓ = v₀ₓ = 1.10 m / s
aₓ = 0
y axis
initially it has no speed, so v₀_y = 0 and when I see the predator it accelerates, until it reaches the speed of 10.6 m / s in a time of t = 1.60 s. let's calculate the acceleration
= v_{oy} -ay t
ay = (v_{oy} -v_{y}) / t
ay = (0 -10.9) / 1.6
ay = -6.8125 m / s²
the sign indicates that the acceleration goes in the negative direction of the y axis
Answer:
In D: 3J
Explanation:
Potential energy: Ep=mgh where m is the mass, h altitude.
In point A: h=20cm=0.2m
Epa=12=0.2×mg. Thus mg=12/0.2=60N
For point D: hd=5cm=0.05m
Epd=mg×0.05=60×0.05=3J
Speed = (frequency) x (wavelength)
Speed = (19 per second) x (7 mm)
Speed = (19 x 7) (per second · mm)
<em>Speed = 133 mm/sec</em>
or you might want to write <em>Speed = 0.133 m/s</em> .