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3 years ago

Select all that apply.

Physics

2 answers:

oee [108]3 years ago

8 0

B and D are the correct answers

Ira Lisetskai [31]3 years ago

7 0

A = false, it will take 0.031 cal to raise 1g Au 1degree while it will take 0.033 cal to raise 1g Hg 1 degree so, although Au will heat up faster, it will not be discernably faster so...
b = true
c = false, Au density > Hg
d = true

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BOTH plant and animal cells contain...<br><br> i need a answer now it's due today please help

Debora [2.8K]

Answer:

I searched it up:

Explanation:

"Structurally, plant and animal cells are very similar because they are both eukaryotic cells. They both contain membrane-bound organelles such as the nucleus, mitochondria, endoplasmic reticulum, Golgi apparatus, lysosomes, and peroxisomes. Both also contain similar membranes, cytosol, and cytoskeletal elements"

Hope this helps ∞<3

4 0

3 years ago

use the general formulas for gravitational force and centripetal force to derive the relationship between speed and orbital radi

MrRissso [65]

Answer:

$v = \sqrt{\frac{GM}{r}}$

Explanation:

The universal law of gravitation is defined as:

$F = G\frac{Mm}{r^{2}}$ (1)

Where G is the gravitational constant, M and m are the masses of the two objects and r is the distance between them.

The centripetal force can be found by means of Newton's second law:

$F = ma$ (2)

Since it is a circular motion, the acceleration can be defined as:

$a = \frac{v^{2}}{r}$ (3)

Where v is the velocity and r is the orbital radius.

Replacing equation (3) in equation (2) it is gotten:

$F = m\frac{v^{2}}{r}$ (4)

Hence,

$m\frac{v^{2}}{r} = G\frac{Mm}{r^{2}}$

Then, v can be isolated:

$mv^{2} = G\frac{Mmr}{r^{2}}$

$mv^{2} = G\frac{Mm}{r}$

$v^{2} = G\frac{Mm}{mr}$

$v^{2} = \frac{GM}{r}$

$v = \sqrt{\frac{GM}{r}}$

So the relationship between speed and orbital radius is given by the expression $v = \sqrt{\frac{GM}{r}}$

8 0

3 years ago

A truck tire rotates at an initial angular speed of 21.5 rad/s. The driver steadily accelerates, and after 3.50 s the tire's ang

erma4kov [3.2K]

Given:

initial angular speed, $\omega _{i}$ = 21.5 rad/s

final angular speed, $\omega _{f}$ = 28.0 rad/s

time, t = 3.50 s

Solution:

Angular acceleration can be defined as the time rate of change of angular velocity and is given by:

$\alpha = \frac{\omega_{f} - \omega _{i}}{t}$

Now, putting the given values in the above formula:

$\alpha = \frac{28.0 - 21.5}{3.50}$

$\alpha = 1.86 m/s^{2}$

Therefore, angular acceleration is:

$\alpha = 1.86 m/s^{2}$

5 0

3 years ago

What has more momentum a large truck stopped at a stop sign or a motorcycle moving down the road.

Alona [7]

<h2>I'm pretty sure it's</h2><h2>"<u>a motorcycle moving down the road.</u>"</h2><h3></h3><h3>The truck isn't moving so the truck cannot have momentum.</h3><h3>Momentum is basically "mass in motion."</h3><h3></h3><h3><em>Please let me know if I am wrong.</em></h3>

4 0

3 years ago

The HR diagram displays the apparent magnitude of stars. <br> True <br> False

harina [27]

Answer: False

Explanation:

HR diagram or Hertzsprung-Russell Diagram shows the relation between the luminosity, spectral class, effective temperature , different stages of star in its life and absolute magnitude.

Absolute magnitude is the apparent magnitude of star when star is at a distance of 10 pc. Thus, the given statement is false. The HR diagram displays the absolute magnitude of stars not the apparent magnitude of stars.

6 0

3 years ago

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