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swat32
3 years ago
14

How long will a plane have to fly continuously with 900 miles per hour in order to cover the same distance as that from Earth to

the next star, Proxima Centauri?
Physics
1 answer:
hammer [34]3 years ago
4 0

I'm not sure about the distance to the nearest star, but it's probably about        4 light-years (L-y).

1 L-y = 1.86 * 10E5 mi/sec * 3600 sec/hr * 24 hr/day * 365 day/yr

1 L-y = 5.9 *10E12 mi   and 4 L-y = 2.3 *10E13 mi    distance to star

2.3 * 10E13 mi / 900 mi/hr = 2.6 * 10E10 hr       hours to star

2.6 * 10E10 hr / (24 hr/day) = 1.1 * 10E9 day     days to star

1.1 * 10E9 day / 365 day/yr = 3 * 10E6 yr = 3 million years to star

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If you know that the period of a pendulum is 1.87 seconds, what is the length of that pendulum? (assume that we are on earth and
laiz [17]

The length of the pendulum is 0.087 m. Option d is correct.

<h3>What is Simple harmonic motion?</h3>

Simple harmonic motion is periodic motion caused by a restoring force that is proportionate to the deviation from equilibrium.

Simple harmonic motion is periodic motion but many other conditions are dependent.

The time period of the pendulum is found as;

\rm T= 2 \pi \sqrt{\frac{L}{g} } \\\\ \rm 1.87 \ sec= 2 \times 3.14  \sqrt{\frac{L}{9.81 m/s^2} } \\\\ L=0.087 \ m

The length of the pendulum is 0.087 m

Hence, option d is correct.

To learn more about the simple harmonic motion refer to the link;

brainly.com/question/17315536

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4 0
3 years ago
A golf club experts an average force of 475 N for 0.006 seconds when it collides with a golf ball on a tee. What is the impulse
Ainat [17]

Answer: 2.85 N.s

Explanation: Impulse is the product of force and time or expressed in the following formula:

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8 0
3 years ago
A truck is moving at 25.0 m/s and sees a barrier in the road 100 m ahead. The truck can decelerate at 4 m/s2. Will the truck hit
Nimfa-mama [501]

Answer:

No, the truck will not cross the barrier.

The closeness of the truck to the barrier is of 21.875 m

Solution:

As per the question:

Velocity of the truck, v = 25.0 m/s

Acceleration of the truck, a = - 4 m/s^{2}

Now,

Since, the barrier at a distance of 100 m. Thus in order to check whether the truck hit the barrier or not, we will see the distance, d it covers by using the kinematic eqn:

v'^{2} = v^{2} + 2ad

Final velocity, v' = 0 m/s

Initial velocity = v

Now,

0^{2} = 25^{2} + 2\times -4d

- 8d = - 625

d = 78.125 m

Thus the truck will not cross the barrier.

Distance between the barrier and the truck:

100 - 78.125 = 21.875 m

6 0
4 years ago
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