Answer:
attached below
Explanation:
a) G(s) = 1 / s( s+2)(s + 4 )
Bode asymptotic magnitude and asymptotic phase plots
attached below
b) G(s) = (s+5)/(s+2)(s+4)
phase angles = tan^-1 w/s , -tan^-1 w/s , tan^-1 w/4
attached below
c) G(s)= (s+3)(s+5)/s(s+2)(s+4)
solution attached below
Answer:
Outside temperature =88.03°C
Explanation:
Conductivity of air-soil from standard table
K=0.60 W/m-k
To find temperature we need to balance energy
Heat generation=Heat dissipation
Now find the value
We know that for sphere
Given that q=500 W
so
By solving that equation we get
=88.03°C
So outside temperature =88.03°C
Answer:
Explanation:
From the question we are told that:
Thickness
Internal Pressure
Shear stress
Elastic modulus
Generally the equation for shear stress is mathematically given by
Where
r_i=internal Radius
Therefore
Generally
Generally the equation for outer diameter is mathematically given by
Therefore
Assuming that the thin cylinder is subjected to integral Pressure
Outer Diameter is