Answer:
= 1.47kJ/K
Explanation: <u>Entropy</u> is the measure of a system's molecular disorder, i.e, the unuseful work a system does.
The nitrogen gas in the insulated tank can be described as an ideal gas, so it can be used the related formulas.
For the entropy, the ratio of initial and final temperatures is needed and as volume is constant, we use:




<u>Specific</u> <u>Heat</u> is the quantity of heat required to increase the temperature 1 degree of a unit mass of a substance. Specific heat of nitrogen at constant volume is
0.743kJ/kg.K
The change in entropy is calculated by
![\Delta S= m[c_{v}ln(\frac{T_{2}}{T_{1}})-Rln(\frac{V_{2}}{V_{1}} )]](https://tex.z-dn.net/?f=%5CDelta%20S%3D%20m%5Bc_%7Bv%7Dln%28%5Cfrac%7BT_%7B2%7D%7D%7BT_%7B1%7D%7D%29-Rln%28%5Cfrac%7BV_%7B2%7D%7D%7BV_%7B1%7D%7D%20%29%5D)
For the nitrogen insulated in a rigid tank:
![\Delta S= m[c_{v}ln(\frac{T_{2}}{T_{1}})]](https://tex.z-dn.net/?f=%5CDelta%20S%3D%20m%5Bc_%7Bv%7Dln%28%5Cfrac%7BT_%7B2%7D%7D%7BT_%7B1%7D%7D%29%5D)
Substituing:
![\Delta S= 3[0.743ln(1.94)]](https://tex.z-dn.net/?f=%5CDelta%20S%3D%203%5B0.743ln%281.94%29%5D)
1.47
The entropy change of nitrogen in an insulated rigid tank is 1.47kJ/K
Answer:
The minimum required thickness for a steel pressure vessel (t) is 2.275 mm
Explanation:
Minimum required thickness is the thickness of a material without corrosion allowance for each component based on the appropriate design that consider pressure, mechanical and structural loading.
Given that:
radius (r) = 65 mm = 65 × 10⁻³ m
Factor of safety (N) = 3.5
Inside presssure (
) = 11 MPa
Outside pressure (
) = 1 MPa
Yield strength (
) = 1000 MPa
Therefore:
, Substituting values,

The minimum required thickness for a steel pressure vessel (t) is given by the equation:
. Substituting values

The minimum required thickness for a steel pressure vessel (t) is 2.275 mm
Answer:
Student A
Explanation:
hope this helps have a great day
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