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3 years ago

What’s the difference between expressed/implied powers, concurrent powers, and reserved powers?.

Physics

1 answer:

Lisa [10]3 years ago

3 0

Answer:

A reserved power is a power specifically reserved to the states. Powers include setting up local governments and determining the speed limit. A concurrent power is a power that is given to both the states and the federal government.

Explanation:

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A distance between two consecutive troughs in a wave motion train produced in a string is 5 cm. Find speed of wave , if two comp

Alexxx [7]

Speed= (frequency) x (wavelength)

= (2 per second) x (5 cm) = <em><u>10 cm/sec .</u></em>

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4 years ago

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MissTica

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3 years ago

I shared a picture of the problem. It’s a basic Physics question and an Algebra question.

julia-pushkina [17]

Hence the expression of ω in terms of m and k is

$\omega = \sqrt{\frac{k}{m}$

Given the expressions;

$T_s = 2 \pi \sqrt{\frac{m}{k} } \ and \ T_s = \frac{2 \pi}{\omega}$

Equating both expressions we will have;

$2 \pi \sqrt{\frac{m}{k} } = \frac{2 \pi}{\omega}$

Divide both equations by 2π

$\frac{2 \pi\sqrt{\frac{m}{2 \pi} } }{2 \pi}=\frac{\frac{2 \pi}{\omega} }{2\pi}\\\sqrt{\frac{m}{2 \pi} } = \frac{1}{\omega}\\$

Square both sides

$(\sqrt{\frac{m}{k} } )^2 = (\frac{1}{\omega} )^2\\\frac{m}{k} = \frac{1}{\omega ^2} \\\omega ^2 = \frac{k}{m}$

Take the square root of both sides

$\sqrt{\omega ^2} =\sqrt{\frac{k}{m} } \\\omega = \sqrt{\frac{k}{m}$

Hence the expression of ω in terms of m and k is

$\omega = \sqrt{\frac{k}{m}$

3 0

3 years ago

A ball is thrown straight up. It passes a 2.00-m-high window 7.50 m off the ground on its path up and takes 1.30 s to go past th

OLga [1]

Answer:

u = 13.67 m/s

Explanation:

given,

window height = 2 m

window is 7.5 m off the ground on its path up

total distance from the ground to pass the window = 2 + 7.5 = 9.5 m

time taken to go past the window = 1.30 s

using equation of motion

$S = u t +\dfrac{1}{2}gt^2$

$(2+7.5)= u\times 1.3 -0.5\times 9.8\times 1.3^2$

$u\times 1.3 = 9.5 + 8.281$

u = 13.67 m/s

hence, the initial velocity of the ball is equal to 13.67 m/s

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3 years ago

If the mass of an object on earth is 40 kilograms it’s mass on the moon is

g100num [7]

Speaking bout mass,
it's mass is still 40Kg on the moon

but it's Weight on the moon is 1/6mg

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4 years ago