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PIT_PIT [208]
3 years ago
6

What’s the difference between expressed/implied powers, concurrent powers, and reserved powers?.

Physics
1 answer:
Lisa [10]3 years ago
3 0

Answer:

A reserved power is a power specifically reserved to the states. Powers include setting up local governments and determining the speed limit. A concurrent power is a power that is given to both the states and the federal government.

Explanation:

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algol13
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who needs more friends on here go to my profile and hit thank you button and friend request and whoever do it first get brianlis
qwelly [4]

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Explanation:

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3 years ago
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Two identical metal spheres A and B are in contact. Both are initially neutral. 1.0× 10 12 electrons are added to sphere A, then
Vilka [71]

Answer:

8 x 10^-8 C on both the spheres.

Explanation:

Number of electrons added to A = 1 x 10^12

As the sphere A and B are identical to each other so the charge is shared equally.

Charge of one electron = 1.6 x 10^-19 C

Charge on A after wards

= number of electrons after wards x charge of one electron

qA = 0.5 x 10^12 x 1.6 x 10^-19 = 8 x 10^-8 C

Similarly, the charge on sphere B afterwards

= number of electrons after wards x charge of one electron

qB = 0.5 x 10^12 x 1.6 x 10^-19 = 8 x 10^-8 C

8 0
4 years ago
Two balls have masses 18 kg and 47 kg. The 18 kg ball has an initial velocity of 76 m/s (to the right) along a line joining the
BigorU [14]

Answer:

The final velocity of 18 kg ball is V_{2} = 42.09 \frac{m}{sec}

Explanation:

Mass of first ball m_{1} = 18 kg

Mass of second ball m_{2} = 47 kg

Initial velocity of 18 kg ball V_{1} = 76 \frac{m}{sec}

Initial velocity of 47 kg ball = 0

Final velocity of 18 kg ball V_{2} = ??

Final velocity of 18 kg ball  is given by the formula

V_{2} = \frac{2 m_{1} V_{1} }{m_{1} + m_{2}  }

Put all the values in above formula we get

V_{2} = 2 × 18 × \frac{76}{65}

V_{2} = 42.09 \frac{m}{sec}

Thus, the final velocity of 18 kg ball is V_{2} = 42.09 \frac{m}{sec}

3 0
3 years ago
Calculate the mass of air of density 1.2kgm-3 in a room of dimensions 8m by 6m by 4m.
77julia77 [94]

Answer:

230.4kg

Explanation:

volume of the room = l× b×h

volume= 8×6×4

volume=192m3

density= mass/volume

hence mass= density × volume

mass= 1.2kgm-3 × 192m3

mass= 230.4kg

5 0
2 years ago
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