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liubo4ka [24]
3 years ago
11

. Inside a laser apparatus, the stimulation and relaxation of electrons in atoms causes many photons with the same to be continu

ously emitted. When these photons are emitted, they travel between two surfaces to form the wave that is represented in the simulation. 2. This wave is the summation of all the photons being introduced with every oscillation, and as they continue to travel, the amplitude . This occurs because the photons are emitted in coherent fashion (constructive interference); however, amplitude when the photons overlap in an incoherent fashion (destructive interference). 3. In a laser device, a small portion of photons are permitted to escape (for use in an application). This is emulated in the simulation, where Damping represents the loss of photons. When Damping is set to Lots the amplitude compared to when Damping is set to None. 4. The generation of multiple wavelengths is possible in some laser producing systems, and the diffraction angle can be to allow the isolation of different wavelengths. 5. Finally, when the power of a laser is described, the wave property that is being referenced is a function of its frequency and .
Physics
1 answer:
mrs_skeptik [129]3 years ago
5 0

Inside a laser apparatus, the stimulation and relaxation of electrons in atoms cause many photons with the same <u>wavelength </u>to be continuously emitted.

From the questions given, the main objective is to fill in the gaps and add important information where necessary. The missing information is highlighted in bold and underlined.

  1. Inside a laser apparatus, the stimulation and relaxation of electrons in atoms cause many photons with the same <u>wavelength </u>to be continuously emitted.

    2. When these photons are emitted, they travel between two <u>reflective </u>

         surfaces to form the wave that is represented in the simulation.

    3. This wave is the summation of all the photons being introduced with

        every oscillation, and as they continue to travel, the amplitude

        <u>increases. </u>

     4.  This occurs because the photons are emitted in a coherent fashion;

        however, amplitude when the photons overlap in an incoherent

        fashion.

     5.  In a laser device, a small portion of photons are permitted to escape

          (for use in an application). This is emulated in the simulation, by

         settling the Damping to Lots such that amplitude <u>remains relatively </u>

         <u>constant </u>when compared to damping of None. (Damping

         represents the Loss of photons.

       6. The generation of multiple wavelengths is possible in some laser

           producing systems, and the diffraction angle can be <u>varied</u> to allow

          the isolation of different wavelengths.

       7. Finally, when the power of a laser is described, the wave property

          that is being referenced is a function of its frequency and

          <u>amplitude.</u>

Therefore, we can conclude that we've fully understood the concept of emission of photons and wavelength in a laser apparatus.

Learn more about wavelength here:

brainly.com/question/23023103?referrer=searchResults

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Grade 2: A more severe sprain, but incomplete tear with moderate pain, swelling and bruising. Although it feels somewhat stable, the damaged areas are tender to the touch and walking is painful.

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6 0
3 years ago
The drawing shows an adiabatically isolated cylinder that is divided initially into two identical parts by an adiabatic partitio
Sveta_85 [38]

Answer:

temperature on left side is 1.48 times the temperature on right

Explanation:

GIVEN DATA:

\gamma = 5/3

T1 = 525 K

T2 = 275 K

We know that

P_1 = \frac{nRT_1}{v}

P_2 = \frac{nrT_2}{v}

n and v remain same at both side. so we have

\frac{P_1}{P_2} = \frac{T_1}{T_2} = \frac{525}{275} = \frac{21}{11}

P_1 = \frac{21}{11} P_2 ..............1

let final pressure is P and temp  T_1 {f} and T_2 {f}

P_1^{1-\gamma} T_1^{\gamma} = P^{1 - \gamma}T_1 {f}^{\gamma}

P_1^{-2/3} T_1^{5/3} = P^{-2/3} T_1 {f}^{5/3} ..................2

similarly

P_2^{-2/3} T_2^{5/3} = P^{-2/3} T_2 {f}^{5/3} .............3

divide 2 equation by 3rd equation

\frac{21}{11}^{-2/3} \frac{21}{11}^{5/3} = [\frac{T_1 {f}}{T_2 {f}}]^{5/3}

T_1 {f} = 1.48 T_2 {f}

thus, temperature on left side is 1.48 times the temperature on right

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antiseptic1488 [7]

Answer:

Explanation:

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liquids do not have definite shape. The take the shape of the container in which they are kept.

gases do not have definite volume.

gases do not have definite shape. They take the shape of the container in which they are kept.

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