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liubo4ka [24]
2 years ago
11

. Inside a laser apparatus, the stimulation and relaxation of electrons in atoms causes many photons with the same to be continu

ously emitted. When these photons are emitted, they travel between two surfaces to form the wave that is represented in the simulation. 2. This wave is the summation of all the photons being introduced with every oscillation, and as they continue to travel, the amplitude . This occurs because the photons are emitted in coherent fashion (constructive interference); however, amplitude when the photons overlap in an incoherent fashion (destructive interference). 3. In a laser device, a small portion of photons are permitted to escape (for use in an application). This is emulated in the simulation, where Damping represents the loss of photons. When Damping is set to Lots the amplitude compared to when Damping is set to None. 4. The generation of multiple wavelengths is possible in some laser producing systems, and the diffraction angle can be to allow the isolation of different wavelengths. 5. Finally, when the power of a laser is described, the wave property that is being referenced is a function of its frequency and .
Physics
1 answer:
mrs_skeptik [129]2 years ago
5 0

Inside a laser apparatus, the stimulation and relaxation of electrons in atoms cause many photons with the same <u>wavelength </u>to be continuously emitted.

From the questions given, the main objective is to fill in the gaps and add important information where necessary. The missing information is highlighted in bold and underlined.

  1. Inside a laser apparatus, the stimulation and relaxation of electrons in atoms cause many photons with the same <u>wavelength </u>to be continuously emitted.

    2. When these photons are emitted, they travel between two <u>reflective </u>

         surfaces to form the wave that is represented in the simulation.

    3. This wave is the summation of all the photons being introduced with

        every oscillation, and as they continue to travel, the amplitude

        <u>increases. </u>

     4.  This occurs because the photons are emitted in a coherent fashion;

        however, amplitude when the photons overlap in an incoherent

        fashion.

     5.  In a laser device, a small portion of photons are permitted to escape

          (for use in an application). This is emulated in the simulation, by

         settling the Damping to Lots such that amplitude <u>remains relatively </u>

         <u>constant </u>when compared to damping of None. (Damping

         represents the Loss of photons.

       6. The generation of multiple wavelengths is possible in some laser

           producing systems, and the diffraction angle can be <u>varied</u> to allow

          the isolation of different wavelengths.

       7. Finally, when the power of a laser is described, the wave property

          that is being referenced is a function of its frequency and

          <u>amplitude.</u>

Therefore, we can conclude that we've fully understood the concept of emission of photons and wavelength in a laser apparatus.

Learn more about wavelength here:

brainly.com/question/23023103?referrer=searchResults

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In Ancient Greece, athletes competing in the long jump used handheld weights called halteres to lengthen their jumps. You are a
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The halter add the distance to the jump in meters is 0.55 m.

<h3>What is projectile?</h3>

When an object is thrown at an angle from the horizontal direction, the object is said to be in projectile motion. The object which follows the projectile motion is called the projectile.

The magnitude of velocity u =10.3 m/s, angle of jumping θ = 22.8 degrees.

Components of velocity in x and y direction are

Vx = 10.3 cos 22.8 = 9.5 m/s

Vy = 10.3 sin 22.8 = 4 m/s

Maximum Range of athlete achieved using halter is given by

R = u²sin2θ /g

where, u = initial velocity, θ is the angle of projection and g is the gravitational acceleration.

Substituting the values, we get

R = (10.3)² sin(2 x 22.8 °) / 2 x 9.81

R = 7.75m

At the peak of jump you throw two 5.5 kg masses horizontally behind you such that their velocity is zero in the ground's reference frame.

The momentum is conserved in this situation,

(M+2m)Vxo =MVx'

Vx' = (M+2m)/M x Vxo'

Change in x component of velocity ΔVx = Vx' -Vxo

Vxo = 2m/M x Vx

Vxo = 2 x 5.5 /78 x 9.5

Vxo = 1.34 s

Maximum height gained when final velocity is zero

Vy = 0 = Vyo -gt

time t = Vyo/g = 4/9.8 = 0.41s'

Increase in range by using of halters is

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ΔR = 1.34 x 0.41

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Thus, the halter add the distance to the jump in meters is 0.55 m.

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For heat transfer purposes, an egg can be considered to be a 5.5-cm-diameter sphere having the properties of water. An egg that
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Answer:

The time taken is   t = 40007 sec  

Explanation:

From the question we are told that

   The diameter of the egg is d_e = 5.5cm  = \frac{5.5}{100} = 5.5*10^{-2}m

    The initial temperature of egg the T_e = 4.3^{o}C

     The temperature of the boiling water T_b = 100^oC

    The heat transfer coefficient is  H  = 800 W/m^2 \cdot K

    The  final temperature is T_e_f = 74^oC

     The  thermal  conductivity of water is k = 0.607 W/m^oC

     The diffusivity of the egg \alpha = 0.146 * 10^{-6} m^2 /s

Using one term approximation

We have the

            \frac{T_e_f - T_b}{T_e - T_b}  = Ae^{-\lambda ^2 \tau}

The radius is  r = \frac{5.5*10^ {-2}}{2} =2.75*10^{-2}m     Note that this radius is approximation to that of  a real egg

    Now we need to obtain the Biot number which help indicate the value of A  \ and \ \lambda to use in the above equation

     The Biot number is mathematically represented as

               Bi = \frac{H r}{k}

Substituting values  

               Bi = \frac{800 * 2.75 *10^{-2}}{0.607}

                    = 36.24

So for this value  which greater than 0.1 the  coefficient \lambda_1 \ and  \ A_1 is  

        \lambda = 3.06632

        A = 1.9942

Substituting this into equation 1 we have

          \frac{74- 100}{4.3 - 100} = 1.9942 e^{-(3.0632^2) \tau}

          0.2717= 1.9942 e^{-(3.0632^2) \tau}

          0.2717= 1.9942 e^{-9.383 \tau}

           0.13624 =  e^{-9.383 \tau}

Taking natural log of both sides

           -1.993 =  -9.383\  \tau

          \tau =  0.2124

    The time required for the egg to be cooked is  mathematically represented as

          t = \frac{\tau r^2}{\alpha }

substituting value  is  

         = \frac{0.2124 * 2.75 *10^{-2}}{0.146 *10^{-6}}

         t = 40007 sec  

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