The gravitational force of the planet pulling on the sun is equal to the gravitational force of the sun pulling on the planet
Explanation:
We can solve this problem by applying Newton's third law, which states that:
<em>"When an object A exerts a force (called </em><em>action</em><em>) on an object B, then object B exerts an equal and opposite force (called </em><em>reaction</em><em>) on object A"</em>
In this problem, we can identify:
- The sun as object A
- The planet as object B
By applying Newton's third law, we can state that:
- The action is the gravitational force exerted by the sun on the planet
- The reaction is the gravitational force exerted by the planet on the sun
According to the law, the two forces are equal in magnitude and opposite in direction: so, we can conclude that
The gravitational force of the planet pulling on the sun is equal to the gravitational force of the sun pulling on the planet
Learn more about Newton's third law:
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An atom in an excited state has higher energy and is less stable than the atom in the ground state.
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Answer:
8.756 rad/s²
Explanation:
Given that:
A motorcycle accelerates uniformly from rest, then initial velocity v_i = 0 m/s
It final velocity v_f = 24.8 m/s
time (t) = 9.87 s
radius (r) of each tire = 0.287 m
Firstly; the linear acceleration of the motor cycle is determined as follows:
=(V_f - v_i)/t
=(24.8-0)/9.87
=2.513 m/s²
Then; the magnitude of angular acceleration
α = /r
=2.513/0.287
=8.756 rad/s²
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For this problem, first, lets recabe information:
v = 0 m/s
t = 3 s
g = 9,82 m/s²
v' = ?
d = ?
First, for calculate the final velocity:
v' = v + g * t
v' = 0 m/s + 9,82 m/s² * 3 s
v' = 29,46 m/s
Now, for calculate how far did it fall:
d = v * t + g * t^2 / 2
Like v = 0 m/s, we can simplificate equation:
d = g * t^2 / 2
d = 9,82 m/s² * (3 s)^2 / 2
d = 9,82 m/s² * 9 s² / 2
d = 88,38 m / 2
d = 44.19 m
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Answer:
Explanation:
Given
Length of beam
mass of beam
Two forces of equal intensity acted in the opposite direction, therefore, they create a torque of magnitude
Also, the beam starts rotating about its center
So, the moment of inertia of the beam is
Torque is the product of moment of inertia and angular acceleration