True conditions
Efficiency of Heat Exchanger are as below:
the heat exchange process between two fluids with different temperatures using solid walls occurs in various engineering applications. The tool to achieve this exchange is a heat exchanger. Some applications like air conditioning, power generation, waste heat recovery, and chemical processing use this device.
The basis of the work of a heat exchanger is that the hot fluid enters the heat exchanger at temperature T1 and its heat capacity is Chot. Also, the cold fluid with the heat capacity of Ccold enters temperature t1; in the meantime, the hot fluid loses its heat, and its temperature drops to T2. It delivers heat to the cold fluid to increase its temperature to t2 and leave the heat exchanger at this temperature.
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The electric field created by Q at the position of q is
.
The given parameters:
- <em>Magnitude of charge, = q</em>
- <em>Spherical charge, = Q</em>
- <em>Force experienced by both charges, = F</em>
The electric field created by Q at the position of q is calculated as follows;

where;
- <em>E is the magnitude of electric field strength </em>
- <em>F is the force experienced by both charges</em>
- <em>Q is the charge</em>
Thus, the electric field created by Q at the position of q is
.
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The tension in the string and the acceleration must be equal for both masses. (See the free body diagrams)
A measure of the quantity of matter is called mass. D.
This is how much of matter is contained in an object. It is different from weight, which is the pull of gravity on an object.
Answer:
A. 24 m, 14 m/s
B. 8.0 m
Explanation:
Given:
x₀ = 6.0 m
v₀ = 4.0 m/s
a = 5.0 m/s²
t = 2.0 s
A. Find: x and v
x = x₀ + v₀ t + ½ at²
x = (6.0 m) + (4.0 m/s) (2.0 s) + ½ (5.0 m/s²) (2.0 m/s)²
x = 24 m
v = at + v₀
v = (5.0 m/s²) (2.0 s) + (4.0 m/s)
v = 14 m/s
B. Find x when v = 6.0 m/s.
v² = v₀² + 2a (x − x₀)
(6.0 m/s)² = (4.0 m/s)² + 2 (5.0 m/s²) (x − 6.0 m)
x = 8.0 m